In mathematics, more specifically in abstract algebra, the commutator subgroup or derived subgroup of a group is the subgroup generated by all the commutators of the group.
The commutator subgroup is important because it is the smallest normal subgroup such that the quotient group of the original group by this subgroup is abelian. In other words,
G/N
N
G
See main article: Commutator. For elements
g
h
g
h
[g,h]=g-1h-1gh
[g,h]
gh=hg
g
h
gh=hg[g,h]
However, the notation is somewhat arbitrary and there is a non-equivalent variant definition for the commutator that has the inverses on the right hand side of the equation:
[g,h]=ghg-1h-1
gh ≠ hg[g,h]
gh=[g,h]hg
An element of G of the form
[g,h]
Here are some simple but useful commutator identities, true for any elements s, g, h of a group G:
[g,h]-1=[h,g],
[g,h]s=[gs,hs],
gs=s-1gs
gs=sgs-1
g
s,
f:G\toH
f([g,h])=[f(g),f(h)].
The first and second identities imply that the set of commutators in G is closed under inversion and conjugation. If in the third identity we take H = G, we get that the set of commutators is stable under any endomorphism of G. This is in fact a generalization of the second identity, since we can take f to be the conjugation automorphism on G,
x\mapstoxs
However, the product of two or more commutators need not be a commutator. A generic example is [''a'',''b''][''c'',''d''] in the free group on a,b,c,d. It is known that the least order of a finite group for which there exists two commutators whose product is not a commutator is 96; in fact there are two nonisomorphic groups of order 96 with this property.
This motivates the definition of the commutator subgroup
[G,G]
G'
G(1)
It follows from this definition that any element of
[G,G]
[g1,h1] … [gn,hn]
n
([g1,h1] … [gn,h
s | |
n]) |
=
s] | |
[g | |
1 |
…
s] | |
[g | |
n |
f([g1,h1] … [gn,hn])=[f(g1),f(h1)] … [f(gn),f(hn)]
so that
f([G,G])\subseteq[H,H]
This shows that the commutator subgroup can be viewed as a functor on the category of groups, some implications of which are explored below. Moreover, taking G = H it shows that the commutator subgroup is stable under every endomorphism of G: that is, [''G'',''G''] is a fully characteristic subgroup of G, a property considerably stronger than normality.
The commutator subgroup can also be defined as the set of elements g of the group that have an expression as a product g = g1 g2 ... gk that can be rearranged to give the identity.
This construction can be iterated:
G(0):=G
G(n):=[G(n-1),G(n-1)] n\inN
G(2),G(3),\ldots
… \triangleleftG(2)\triangleleftG(1)\triangleleftG(0)=G
Gn:=[Gn-1,G]
For a finite group, the derived series terminates in a perfect group, which may or may not be trivial. For an infinite group, the derived series need not terminate at a finite stage, and one can continue it to infinite ordinal numbers via transfinite recursion, thereby obtaining the transfinite derived series, which eventually terminates at the perfect core of the group.
Given a group
G
G/N
[G,G]\subseteqN
The quotient
G/[G,G]
G
G
G\operatorname{ab
G\operatorname{ab
There is a useful categorical interpretation of the map
\varphi:G → G\operatorname{ab
\varphi
G
H
H
f:G\toH
F:G\operatorname{ab
f=F\circ\varphi
G\operatorname{ab
G\toG/[G,G]
The abelianization functor is the left adjoint of the inclusion functor from the category of abelian groups to the category of groups. The existence of the abelianization functor Grp → Ab makes the category Ab a reflective subcategory of the category of groups, defined as a full subcategory whose inclusion functor has a left adjoint.
Another important interpretation of
G\operatorname{ab
H1(G,Z)
G
A group
G
A group
G
A group with
G(n)=\{e\}
A group with
G(n) ≠ \{e\}
A group with
G(\alpha)=\{e\}
See main article: articles and Perfect group. Whenever a group
G
G(1)=G
\operatorname{SL}n(k)
k
\operatorname{GL}n(k)
\operatorname{SL}n(k)
n\ne2
Since the derived subgroup is characteristic, any automorphism of G induces an automorphism of the abelianization. Since the abelianization is abelian, inner automorphisms act trivially, hence this yields a map
\operatorname{Out}(G)\to\operatorname{Aut}(Gab)