In mathematics, Darboux's theorem is a theorem in real analysis, named after Jean Gaston Darboux. It states that every function that results from the differentiation of another function has the intermediate value property: the image of an interval is also an interval.
When ƒ is continuously differentiable (ƒ in C1([''a'',''b''])), this is a consequence of the intermediate value theorem. But even when ƒ′ is not continuous, Darboux's theorem places a severe restriction on what it can be.
Let
I
f\colonI\to\R
f'
a
b
I
a<b
y
f'(a)
f'(b)
x
[a,b]
f'(x)=y
Proof 1. The first proof is based on the extreme value theorem.
If
y
f'(a)
f'(b)
x
a
b
y
f'(a)
f'(b)
f'(a)>y>f'(b)
\varphi\colonI\to\R
\varphi(t)=f(t)-yt
f'(a)<y<f'(b)
\varphi
[a,b]
Since
\varphi
[a,b]
\varphi
[a,b]
[a,b]
Because
\varphi'(a)=f'(a)-y>0
\varphi
a
(\varphi(t)-\varphi(a))/(t-a)\leq0
t\in(a,b]
\varphi'(a)\leq0
Likewise, because
\varphi'(b)=f'(b)-y<0
\varphi
b
Therefore,
\varphi
x\in(a,b)
\varphi'(x)=0
f'(x)=y
Proof 2. The second proof is based on combining the mean value theorem and the intermediate value theorem.[1] [2]
Define
c=
1 | |
2 |
(a+b)
a\leqt\leqc,
\alpha(t)=a
\beta(t)=2t-a
c\leqt\leqb,
\alpha(t)=2t-b
\beta(t)=b
Thus, for
t\in(a,b)
a\leq\alpha(t)<\beta(t)\leqb
g(t)=
(f\circ\beta)(t)-(f\circ\alpha)(t) | |
\beta(t)-\alpha(t) |
a<t<b
g
(a,b)
Furthermore,
g(t) → {f}'(a)
t → a
g(t) → {f}'(b)
t → b
y\in({f}'(a),{f}'(b))
t0\in(a,b)
g(t0)=y
t0
From the Mean Value Theorem, there exists a point
x\in(\alpha(t0),\beta(t0))
{f}'(x)=g(t0)
{f}'(x)=y
A Darboux function is a real-valued function ƒ which has the "intermediate value property": for any two values a and b in the domain of ƒ, and any y between ƒ(a) and ƒ(b), there is some c between a and b with ƒ(c) = y.[4] By the intermediate value theorem, every continuous function on a real interval is a Darboux function. Darboux's contribution was to show that there are discontinuous Darboux functions.
Every discontinuity of a Darboux function is essential, that is, at any point of discontinuity, at least one of the left hand and right hand limits does not exist.
An example of a Darboux function that is discontinuous at one point is the topologist's sine curve function:
x\mapsto\begin{cases}\sin(1/x)&forx\ne0,\ 0&forx=0.\end{cases}
By Darboux's theorem, the derivative of any differentiable function is a Darboux function. In particular, the derivative of the function
x\mapstox2\sin(1/x)
An example of a Darboux function that is nowhere continuous is the Conway base 13 function.
Darboux functions are a quite general class of functions. It turns out that any real-valued function ƒ on the real line can be written as the sum of two Darboux functions.[5] This implies in particular that the class of Darboux functions is not closed under addition.
A strongly Darboux function is one for which the image of every (non-empty) open interval is the whole real line. The Conway base 13 function is again an example.[4]