The counting lemmas this article discusses are statements in combinatorics and graph theory. The first one extracts information from
\epsilon
G
H
G
H
Whenever we have an
\epsilon
U,V
G
(U,V)
d(U,V)
d(U,V)
\epsilon
In a setting where we have several clusters of vertices, some of the pairs between these clusters being
\gamma
H
G
H
G
The above intuition works, yet there are several important conditions that must be satisfied in order to have a complete statement of the theorem; for instance, the pairwise densities are at least
\varepsilon
\gamma-1
\gamma\leq\varepsilonh/4h
This theorem is a generalization of the triangle counting lemma, which states the above but withStatement of the theorem
If
is a graph with verticesH
and1, … ,h
edges, andm
is a graph with (not necessarily disjoint) vertex subsetsG
, such thatW1, … ,Wh
for all|Wi|\geq\gamma-1
and for every edgei=1,\ldots,h
of(i,j)
the pairH
is(Wi,Wj)
-regular with density\gamma
andd(Wi,Wj)>\varepsilon
, then\gamma\leq\varepsilonh/4h
contains at leastG
many copies of2-h\varepsilonm|W1| ⋅ \ldots ⋅ |Wh|
with the copy of vertexH
ini
.Wi
H=K3
Triangle counting Lemma
Let
be a graph onG
vertices, and letn
be subsets ofX,Y,Z
which are pairwiseV(G)
-regular, and suppose the edge densities\epsilon
are all at leastdXY,dXZ,dYZ
. Then the number of triples2\epsilon
such that(x,y,z)\inX x Y x Z
form a triangle inx,y,z
is at leastG
Since
(X,Y)
\varepsilon|X|
X
(dXY-\varepsilon)|Y|
Y
X
Y
(X,Y)
X
Y
By an analogous argument in the pair
(X,Z)
\varepsilon|X|
X
(dXZ-\varepsilon)|Z|
Z
X
X'\subseteqX
(1-2\varepsilon)|X|
x\inX'
(dXY-\varepsilon)|Y|
Y
(dXZ-\varepsilon)|Z|
Z
We also know that
dXY,dXZ\geq2\varepsilon
(Y,Z)
\varepsilon
x
Y
x
Z
(dYZ-\varepsilon)
\varepsilon
Y
Z
Summing up, for each of these at least
(1-2\varepsilon)|X|
x\inX'
(dXY-\epsilon)(dXZ-\epsilon)(dYZ-\epsilon)|Y||Z|
x
Y
x
Z
Idea of proof of graph counting lemma:The general proof of the graph counting lemma extends this argument through a greedy embedding strategy; namely, vertices of
H
The space
\tilde{l{W}}0
\delta\Box
(\tilde{l{W}}0,\delta\Box)
F
F
The cut norm of
W:[0,1]2\toR
\|W\|\square=\supS,\left|\intS x W\right|
S
T
The cut distance is defined as
\delta\square(U,W)=inf\phi||U-W\phi||\square
W\phi(x,y)
W(\phi(x),\phi(y))
\phi
Graphon Counting Lemma
For graphons
and graphW,U
, we haveF
, where|t(F,W)-t(F,U)|\le|E(F)|\delta\square(W,U)
denotes the number of edges of graph|E(F)|
.F
It suffices to prove Indeed, by considering the above, with the right hand side expression having a factor
\|W-U\phi\|\Box
\|W-U\|\Box
\phi
Step 1: Reformulation. We prove a reformulation of the cut norm, which is by definition the left hand side of the following equality. The supremum in the right hand side is taken among measurable functions
u
v
Here's the reason for the above to hold: By taking
u=1S
u=1T
u,v
u,v
0
1
Step 2: Proof for
F=K3
F=K3
By Step 1, we have that for a fixed
z
Therefore, when integrating over all
\left|\int [0,1]2 (W-U)(x,y)W(x,z)W(y,z)dxdy\right|\le\|W-U\|\square
z\in[0,1]
Using this bound on each of the three summands, we get that the whole sum is bounded by
\left|\int [0,1]3 (W-U)(x,y)W(x,z)W(y,z)dxdydz\right|\le\|W-U\|\square
3\|W-U\|\square
Step 3: General case. For a general graph
F
The above lemma follows from a straightforward expansion of the right hand side. Then, by the triangle inequality of norm, we have the followingLemma.
The following expression holds:
Here, each absolute value term in the sum is bounded by the cut norm
\|W-U\|\square
ui
vi
i
|t(F,W)-t(F,U)|\le|E(F)| \delta\square(W,U)