In number theory, a congruent number is a positive integer that is the area of a right triangle with three rational number sides.[1] A more general definition includes all positive rational numbers with this property.
The sequence of (integer) congruent numbers starts with
5, 6, 7, 13, 14, 15, 20, 21, 22, 23, 24, 28, 29, 30, 31, 34, 37, 38, 39, 41, 45, 46, 47, 52, 53, 54, 55, 56, 60, 61, 62, 63, 65, 69, 70, 71, 77, 78, 79, 80, 84, 85, 86, 87, 88, 92, 93, 94, 95, 96, 101, 102, 103, 109, 110, 111, 112, 116, 117, 118, 119, 120, ...
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ||
---|---|---|---|---|---|---|---|---|---|
- | - | - | - | C | C | C | - | ||
9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | ||
- | - | - | - | C | C | C | - | ||
17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 | ||
- | - | - | S | C | C | C | S | ||
25 | 26 | 27 | 28 | 29 | 30 | 31 | 32 | ||
- | - | - | S | C | C | C | - | ||
33 | 34 | 35 | 36 | 37 | 38 | 39 | 40 | ||
- | C | - | - | C | C | C | - | ||
41 | 42 | 43 | 44 | 45 | 46 | 47 | 48 | ||
C | - | - | - | S | C | C | - | ||
49 | 50 | 51 | 52 | 53 | 54 | 55 | 56 | ||
- | - | - | S | C | S | C | S | ||
57 | 58 | 59 | 60 | 61 | 62 | 63 | 64 | ||
- | - | - | S | C | C | S | - | ||
65 | 66 | 67 | 68 | 69 | 70 | 71 | 72 | ||
C | - | - | - | C | C | C | - | ||
73 | 74 | 75 | 76 | 77 | 78 | 79 | 80 | ||
- | - | - | - | C | C | C | S | ||
81 | 82 | 83 | 84 | 85 | 86 | 87 | 88 | ||
- | - | - | S | C | C | C | S | ||
89 | 90 | 91 | 92 | 93 | 94 | 95 | 96 | ||
- | - | - | S | C | C | C | S | ||
97 | 98 | 99 | 100 | 101 | 102 | 103 | 104 | ||
- | - | - | - | C | C | C | - | ||
105 | 106 | 107 | 108 | 109 | 110 | 111 | 112 | ||
- | - | - | - | C | C | C | S | ||
113 | 114 | 115 | 116 | 117 | 118 | 119 | 120 | ||
- | - | - | S | S | C | C | S |
For example, 5 is a congruent number because it is the area of a (20/3, 3/2, 41/6) triangle. Similarly, 6 is a congruent number because it is the area of a (3,4,5) triangle. 3 and 4 are not congruent numbers.
If is a congruent number then is also a congruent number for any natural number (just by multiplying each side of the triangle by), and vice versa. This leads to the observation that whether a nonzero rational number is a congruent number depends only on its residue in the group
Q*/Q*2,
where
Q*
Every residue class in this group contains exactly one square-free integer, and it is common, therefore, only to consider square-free positive integers, when speaking about congruent numbers.
The question of determining whether a given rational number is a congruent number is called the congruent number problem. This problem has not (as of 2019) been brought to a successful resolution. Tunnell's theorem provides an easily testable criterion for determining whether a number is congruent; but his result relies on the Birch and Swinnerton-Dyer conjecture, which is still unproven.
Fermat's right triangle theorem, named after Pierre de Fermat, states that no square number can be a congruent number. However, in the form that every congruum (the difference between consecutive elements in an arithmetic progression of three squares) is non-square, it was already known (without proof) to Fibonacci.[2] Every congruum is a congruent number, and every congruent number is a product of a congruum and the square of a rational number.[3] However, determining whether a number is a congruum is much easier than determining whether it is congruent, because there is a parameterized formula for congrua for which only finitely many parameter values need to be tested.[4]
n is a congruent number if and only if the system
x2-ny2=u2
x2+ny2=v2
has a solution where
x,y,u
v
Given a solution, the three numbers
u2
x2
v2
ny2
Furthermore, if there is one solution (where the right-hand sides are squares), then there are infinitely many: given any solution
(x,y)
(x',y')
x'=(xu)2+n(yv)2,
y'=2xyuv.
For example, with
n=6
x2-6y2=u2,
x2+6y2=v2.
x=5,y=2
u=1,v=7
x'=(5 ⋅ 1)2+6(2 ⋅ 7)2=1201,
y'=2 ⋅ 5 ⋅ 2 ⋅ 1 ⋅ 7=140.
x'
y'
u'2=12012-6 ⋅ 1402=1324801=11512,
v'2=12012+6 ⋅ 1402=1560001=12492.
Using
x'=1201,y'=140,u',v'
u''=1,727,438,169,601
v''=2,405,943,600,001
Given
x,y,u
v
a,b
c
a2+b2=c2
ab | |
2 |
=n
a=
v-u | |
y |
, b=
v+u | |
y |
, c=
2x | |
y |
.
a,b
c
n
The above values
(x,y,u,v)=(5,2,1,7)
(a,b,c)=(3,4,5)
(1201,140,1151,1249)
(a,b,c)=(7/10,120/7,1201/70)
n=6
The question of whether a given number is congruent turns out to be equivalent to the condition that a certain elliptic curve has positive rank. An alternative approach to the idea is presented below (as can essentially also be found in the introduction to Tunnell's paper).
Suppose,, are numbers (not necessarily positive or rational) which satisfy the following two equations:
\begin{align} a2+b2&=c2,\\ \tfrac{1}{2}ab&=n. \end{align}
Then set and.A calculation shows
y2=x3-n2x
Conversely, if and are numbers which satisfy the above equation and is not 0, set,, and . A calculation shows these three numberssatisfy the two equations for,, and above.
These two correspondences between and are inverses of each other, sowe have a one-to-one correspondence between any solution of the two equations in,, and and any solution of the equation in and with nonzero. In particular,from the formulas in the two correspondences, for rational we see that,, and arerational if and only if the corresponding and are rational, and vice versa.(We also have that,, and are all positive if and only if and are all positive;from the equation we see that if and are positive then must be positive, so the formula for above is positive.)
Thus a positive rational number is congruent if and only if the equation has a rational point with not equal to 0.It can be shown (as an application of Dirichlet's theorem on primes in arithmetic progression)that the only torsion points on this elliptic curve are those with equal to 0, hence theexistence of a rational point with nonzero is equivalent to saying the elliptic curve has positive rank.
Another approach to solving is to start with integer value of n denoted as N and solve
N2=ed2+e2
where
\begin{align} c&=n2/e+e\\ a&=2n\\ b&=n2/e-e \end{align}
For example, it is known that for a prime number, the following holds:
It is also known that in each of the congruence classes, for any given there are infinitely many square-free congruent numbers with prime factors.[7]