In mathematics, especially in the areas of numerical analysis called numerical partial differential equations, a compact stencil is a type of stencil that uses only nine nodes for its discretization method in two dimensions. It uses only the center node and the adjacent nodes. For any structured grid utilizing a compact stencil in 1, 2, or 3 dimensions the maximum number of nodes is 3, 9, or 27 respectively. Compact stencils may be compared to non-compact stencils. Compact stencils are currently implemented in many partial differential equation solvers, including several in the topics of CFD, FEA, and other mathematical solvers relating to PDE's.[1] [2]
The two point stencil for the first derivative of a function is given by:
f'(x | ||||
|
+O\left(h2\right)
This is obtained from the Taylor series expansion of the first derivative of the function given by:
\begin{array}
{l} f'(x | - | ||||
|
f(2)(x0) | |
2! |
h-
f(3)(x0) | |
3! |
h2-
f(4)(x0) | |
4! |
h3+ … \end{array}
Replacing
h
-h
\begin{array}
{l} f'(x | ||||
|
+
f(2)(x0) | |
2! |
h-
f(3)(x0) | |
3! |
h2+
f(4)(x0) | |
4! |
h3+ … \end{array}
Addition of the above two equations together results in the cancellation of the terms in odd powers of
h
\begin{array}
{l} 2f'(x | - | ||||
|
f\left(x0-h\right)-f(x0) | -2 | |
h |
f(3)(x0) | |
3! |
h2+ … \end{array}
\begin{array}
{l} f'(x | ||||
|
-
f(3)(x0) | |
3! |
h2+ … \end{array}
\begin{array}
{l} f'(x | ||||
|
+O\left(h2\right) \end{array}
For example, the three point stencil for the second derivative of a function is given by:
\begin{array}{l} f(2)
(x | ||||
|
+O\left(h2\right) \end{array}
This is obtained from the Taylor series expansion of the first derivative of the function given by:
\begin{array}
{l} f'(x | - | ||||
|
f(2)(x0) | |
2! |
h-
f(3)(x0) | |
3! |
h2-
f(4)(x0) | |
4! |
h3+ … \end{array}
Replacing
h
-h
\begin{array}
{l} f'(x | ||||
|
+
f(2)(x0) | |
2! |
h-
f(3)(x0) | |
3! |
h2+
f(4)(x0) | |
4! |
h3+ … \end{array}
Subtraction of the above two equations results in the cancellation of the terms in even powers of
h
\begin{array}{l} 0=
f\left(x0+h\right)-f(x0) | + | |
h |
f\left(x0-h\right)-f(x0) | |
h |
-2
f(2)(x0) | |
2! |
h-2
f(4)(x0) | |
4! |
h3+ … \end{array}
\begin{array}{l} f(2)
(x | ||||
|
-2
f(4)(x0) | |
4! |
h2+ … \end{array}
\begin{array}{l} f(2)
(x | ||||
|
+O\left(h2\right) \end{array}