| Chorula | |
| Settlement Type: | Village |
| Total Type: | |
| Subdivision Type: | Country |
| Subdivision Name: | Poland |
| Subdivision Type1: | Voivodeship |
| Subdivision Name1: | Opole |
| Subdivision Type2: | County |
| Subdivision Name2: | Krapkowice |
| Subdivision Type3: | Gmina |
| Subdivision Name3: | Gogolin |
| Coordinates: | 50.5333°N 75°W |
| Pushpin Map: | Poland |
| Pushpin Label Position: | right |
| Population Total: | 640 |
| Website: | http://www.chorula.pl/ |
Chorula is a village in the administrative district of Gmina Gogolin, within Krapkowice County, Opole Voivodeship, in south-western Poland.[1] It lies approximately 7km (04miles) north-west of Gogolin, 80NaN0 north of Krapkowice, and 150NaN0 south of the regional capital Opole.