Cantor's intersection theorem refers to two closely related theorems in general topology and real analysis, named after Georg Cantor, about intersections of decreasing nested sequences of non-empty compact sets.
Theorem. Let
S
S
(Ck)k
C0\supsetC1\supset … \supsetCn\supsetCn+1\supset … ,
it follows that
infty | |
cap | |
k=0 |
Ck ≠ \emptyset.
The closedness condition may be omitted in situations where every compact subset of
S
S
Proof. Assume, by way of contradiction, that
infty | |
{stylecap | |
k=0 |
Ck}=\emptyset
k
Uk=C0\setminusCk
infty | |
{stylecup | |
k=0 |
Uk}=C0\setminus
infty | |
{stylecap | |
k=0 |
Ck}
infty | |
{stylecap | |
k=0 |
Ck}=\emptyset
infty | |
{stylecup | |
k=0 |
Uk}=C0
Ck
S
C0
Uk
C0
C0
Since
C0\subsetS
\{Uk\vertk\geq0\}
C0
C0
\{U | |
k1 |
,
U | |
k2 |
,\ldots,
U | |
km |
\}
M=max1\leq{ki}
m | |
{stylecup | |
i=1 |
U | |
ki |
U1\subsetU2\subset … \subsetUn\subsetUn+1 …
(Ck)k
C0={stylecup
m | |
i=1 |
U | |
ki |
CM=C0\setminusUM=\emptyset
The theorem in real analysis draws the same conclusion for closed and bounded subsets of the set of real numbers
R
(Ck)k
R
This version follows from the general topological statement in light of the Heine - Borel theorem, which states that sets of real numbers are compact if and only if they are closed and bounded. However, it is typically used as a lemma in proving said theorem, and therefore warrants a separate proof.
As an example, if
Ck=[0,1/k]
(Ck)k
\{0\}
Ck=(0,1/k)
Ck=[k,infty)
This version of the theorem generalizes to
Rn
n
Ck=[\sqrt{2},\sqrt{2}+1/k]=(\sqrt{2},\sqrt{2}+1/k)
are closed and bounded, but their intersection is empty.
Note that this contradicts neither the topological statement, as the sets
Ck
A simple corollary of the theorem is that the Cantor set is nonempty, since it is defined as the intersection of a decreasing nested sequence of sets, each of which is defined as the union of a finite number of closed intervals; hence each of these sets is non-empty, closed, and bounded. In fact, the Cantor set contains uncountably many points.
Theorem. Let
(Ck)k
R
C0\supsetC1\supset … Cn\supsetCn+1 … .
Then,
infty | |
cap | |
k=0 |
Ck ≠ \emptyset.
Proof. Each nonempty, closed, and bounded subset
Ck\subsetR
xk
k
xk+1\inCk+1\subsetCk
xk\lexk+1
so
(xk)k
C0
x=\limk\toxk.
For fixed
k
xj\inCk
j\geqk
Ck
x
x\inCk
k
x
infty | |
{stylecap | |
k=0 |
Ck}
In a complete metric space, the following variant of Cantor's intersection theorem holds.
Theorem. Suppose that
X
(Ck)k
X
\limk\toinfty\operatorname{diam}(Ck)=0,
where
\operatorname{diam}(Ck)
\operatorname{diam}(Ck)=\sup\{d(x,y)\midx,y\inCk\}.
Then the intersection of the
Ck
infty | |
cap | |
k=1 |
Ck=\{x\}
for some
x\inX
Proof (sketch). Since the diameters tend to zero, the diameter of the intersection of the
Ck
xk\inCk
k
Ck
Ck
xk
x
Ck
x
Ck
x
Ck
k
Ck
x
A converse to this theorem is also true: if
X
X
(xk)k
X
Ck
(xj)j