1988 CONCACAF Champions' Cup explained

Year:1988
Dates:30 November – 21 December
Size:275
Caption:Estadio Nacional in Tegucigalpa hosted the final round
Num Teams:4
Associations:4
Champion Other: Olimpia
Count:2
Second Other: Defence Force
Matches:6
Goals:9
Prevseason:1987
Nextseason:1989

The 1988 CONCACAF Champions' Cup was the 24th. edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's club champion of association football in the CONCACAF region and was played from 11 March till 21 December 1988.

The teams were split in 2 zones, North/Central America and Caribbean, (as North and Central America sections combined to qualify one team for the final), each one qualifying two teams to the final tournament.

Hondurean club Olimpia beat Trinidarian side Defence Force 4–0 on aggregate to become champions,[1] [2]

North/Central American Zone

Preliminary round

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First round

North American Zone

Central American Zone

Played in Guatemala City

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Second round

Central American Zone

Played in Tegucigalpa

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Third round

Central American Zone

Played in Tegucigalpa

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Fourth round

North/Central American Zone

Caribbean Zone

First round

Matches and results unknown:
Zenith
Robinhood
Sion Hill
Cardinals

Second round

Matches and results unknown:
La Gauloise
Seba United
Sport Guyanais

Semi-finals

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Final

First leg

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Second leg

Notes and References

  1. https://www.rsssf.org/tablesc/cacups88.html Copa de Campeones 1988
  2. https://www.elheraldo.hn/deportes/1118377-466/olimpia-y-sus-tres-hazañas-en-la-concacaf Olimpia y sus tres hazañas