1970 CONCACAF Champions' Cup explained

Tourney Name:	CONCACAF Champions' Cup
Year:	1970
Other Titles:	Copa de Campeones Concacaf
Dates:	26 April – 5 June
Num Teams:	12
Associations:	12
Champion Other:	Cruz Azul
Count:	2
Prevseason:	1969
Nextseason:	1971

The 1970 CONCACAF Champions' Cup was the 6th edition of the annual international club association football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup

It was played from 26 April to 5 June 1970 under the home/away match system. The teams were split into three zones (North American, Central American and Caribbean), each qualifying the winner to the final tournament. The final tournament was not held and Cruz Azul were declared CONCACAF Champions after Deportivo Saprissa and SV Transvaal withdrew.

Cruz Azul from Mexico won the competition for the second time in their history, having also won the 1969 Champions' Cup the previous year.^[1]

North American Zone

• Cruz Azul won 6–0 on aggregate score.

Central American Zone

First round

Torneo Centroamericano de Concacaf 1970Group A

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• Saprissa advance to final round.

Group B

• Olimpia won 3–2 on aggregate score.

Final Round

• Saprissa won 5–1 on aggregate score and advance to final round.

Caribbean Zone

First round

• Transvaal won 4–1 on aggregate score.

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• Racing Haïtien won 6–3 on aggregate score.

Second round

• Unknown results; Santos wins round.

Final Round

• Transvaal won 5–1 on aggregate score.

Semi-finals

The semi-finals and final were scratched and Cruz Azul were declared CONCACAF Champions after Deportivo Saprissa and Transvaal both withdrew.

Notes and References

1. Web site: Goloboy . Jim . Stokkermans . Karel . Central American Club Competitions 1970 . RSSSF.org . 17 June 2023 . 9 May 2019.