| Tourney Name: | CONCACAF Champions' Cup |
| Year: | 1969 |
| Other Titles: | Copa de Campeones Concacaf |
| Dates: | 25 April – 30 September |
| Num Teams: | 10 |
| Associations: | 9 |
| Champion Other: |  Cruz Azul |
| Second Other: | Comunicaciones |
| Third Other: | Saprissa |
| Matches: | 18 |
| Goals: | 53 |
| Prevseason: | 1968 |
| Nextseason: | 1970 |
The 1969 CONCACAF Champions' Cup was the 5th edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's football club champion in the CONCACAF region.
The tournament was played by 10 teams of 9 nations: Netherlands Antilles, Bermuda, El Salvador, Haiti, Guatemala, Honduras, Mexico, Nicaragua, Costa Rica. It was played from 25 April to 30 September 1969 under the home/away match system and for the first time, the teams were not split into zones, playing in a straight round system.[1] [2]
Cruz Azul from Mexico won the final after beating Guatemalan club Comunicaciones 1–0 in the second leg,[3] becoming CONCACAF champion for the first time in its history.[1] [4]
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