Borel subalgebra explained

ak{g}

is a maximal solvable subalgebra. The notion is named after Armand Borel.

If the Lie algebra

ak{g}

is the Lie algebra of a complex Lie group, then a Borel subalgebra is the Lie algebra of a Borel subgroup.

Borel subalgebra associated to a flag

Let

akg=ak{gl}(V)

be the Lie algebra of the endomorphisms of a finite-dimensional vector space V over the complex numbers. Then to specify a Borel subalgebra of

akg

amounts to specify a flag of V; given a flag

V=V0 \supsetV1\supset\supsetVn=0

, the subspace

akb=\{x\inakg\midx(Vi)\subsetVi,1\lei\len\}

is a Borel subalgebra, and conversely, each Borel subalgebra is of that form by Lie's theorem. Hence, the Borel subalgebras are classified by the flag variety of V.

Borel subalgebra relative to a base of a root system

Let

akg

be a complex semisimple Lie algebra,

akh

a Cartan subalgebra and R the root system associated to them. Choosing a base of R gives the notion of positive roots. Then

akg

has the decomposition

akg=akn-akhakn+

where

akn\pm=\sum\alphaak{g}\pm

. Then

akb=akhakn+

is the Borel subalgebra relative to the above setup. (It is solvable since the derived algebra

[akb,akb]

is nilpotent. It is maximal solvable by a theorem of Borel–Morozov on the conjugacy of solvable subalgebras.)

Given a

akg

-module V, a primitive element of V is a (nonzero) vector that (1) is a weight vector for

akh

and that (2) is annihilated by

ak{n}+

. It is the same thing as a

akb

-weight vector (Proof: if

h\inakh

and

e\inak{n}+

with

[h,e]=2e

and if

ak{b}v

is a line, then

0=[h,e]v=2ev

.)

See also

References