1912 Belgian general election explained

Country:Belgium
Type:parliamentary
Previous Election:1910 Belgian general election
Previous Year:1910
Next Election:1914 Belgian general election
Next Year:1914
Seats For Election:All 186 seats in the Chamber of Representatives
93 of 120 seats in the Senate
Election Date:2 June 1912
Image1:DeBroqueville.jpg
Leader1:Charles de Broqueville
Party1:Catholic Party (Belgium)
Seats1:101
Popular Vote1:1,337,315
Percentage1:51.01%
Leader2:N/A
Party2:LiberalSocialist
Seats2:45
Popular Vote2:710,459
Percentage2:27.10%
Color2:800080
Image3:3x4.svg
Party3:Liberal Party (Belgium)
Seats3:21
Popular Vote3:291,084
Percentage3:11.10%
Image4:3x4.svg
Leader4:Laurent Vandersmissen
Party4:Belgian Labour Party
Seats4:18
Popular Vote4:243,338
Percentage4:9.28%
Party5:Christene Volkspartij
Seats5:1
Popular Vote5:19,317
Percentage5:0.74%
Government
Posttitle:Government after election
Before Election:De Broqueville I
Before Party:Catholic Party (Belgium)
After Election:De Broqueville I
After Party:Catholic Party (Belgium)

Full general elections were held in Belgium on 2 June, 1912.[1]

Background

Catholics had formed the government continuously since 1884. Minister Schollaert had drafted a controversial education law, because of which he was forced to resign in June 1911. He was succeeded by a government led by Charles de Broqueville. The education law was intended to financially equalise public and private education, which was opposed by liberals and socialists as it benefited private (Catholic) schools. Both opposition parties, united against Catholics, were expected to win the elections. King Albert I was preparing to switch to a progressive government headed by liberal Paul Hymans. However, the elections unexpectedly increased the majority of the Catholic Party, which won 101 of the 186 seats in the Chamber of Representatives and 54 of the 93 seats in the Senate.[2] Consequently, the incumbent Catholic government headed by Charles de Broqueville continued after the elections.

Electoral system

These elections were the first full general elections since 27 May 1900, when a proportional system using the D'Hondt method was introduced. Since 1893, there was universal suffrage with plural voting. Hence, there were more votes than the 1,745,666 who could vote in these Chamber elections (out of a population of 7,571,387 in the country).

Following the population census, the number of seats in the Chamber of Representatives increased from 166 to 186. The number of directly elected seats in the Senate (half the number of Chamber seats) consequently increased from 83 to 93; the number of provincial senators remained at 27.

Results

Senate

Constituencies

The distribution of seats among the electoral districts was as follows.[3] Several arrondissements got one or more additional seats, following the population census. With Neufchâteau-Virton receiving an extra seat, every electoral district now had at minimum, three seats in the Chamber.

ProvinceArrondissement(s)Chamber ChangeSenate Change
15 +2 7 +1
5 +1 5 +1
4 +1
Elected by the provincial council 3
3 4 +1
4 +1
Elected by the provincial council 2
5 4
3
12 +1 6 +1
4 +1 4
4
Elected by the provincial council 4
4 2
5 +1 3 +1
5 4
3
5 +1 2
Elected by the provincial council 3
7 +1 3
26 +5 13 +2
4 2
Elected by the provincial council 4
6 3
11 +2 7 +1
3
7 +1 5
4
Elected by the provincial council 4
4 2
13 +1 7 +1
5 2
Elected by the provincial council 3
3 3
3 +1
Elected by the provincial council 2
5 5 +1
4
Elected by the provincial council 2
Total 186 +20 120 +10

Notes and References

  1. Book: Dieter Nohlen

    . Elections in Europe: A data handbook . Nohlen . Dieter . Dieter Nohlen . Stöver . Philip . 31 May 2010 . Nomos Verlagsgesellschaft . 289 . 978-3-8329-5609-7.

  2. Nohlen & Stöver, pp308-310
  3. http://www.dekamer.be/digidoc/DPS/K3055/K30550008/K30550008.PDF List of members of the Chamber of Representatives (1912)