Bapat–Beg theorem explained

In probability theory, the Bapat–Beg theorem gives the joint probability distribution of order statistics of independent but not necessarily identically distributed random variables in terms of the cumulative distribution functions of the random variables. Ravindra Bapat and M.I. Beg published the theorem in 1989,[1] though they did not offer a proof. A simple proof was offered by Hande in 1994.[2]

Often, all elements of the sample are obtained from the same population and thus have the same probability distribution. The Bapat–Beg theorem describes the order statistics when each element of the sample is obtained from a different statistical population and therefore has its own probability distribution.

Statement

Let

X1,X2,\ldots,Xn

be independent real valued random variables with cumulative distribution functions respectively

F1(x),F2(x),\ldots,Fn(x)

. Write

X(1),X(2),\ldots,X(n)

for the order statistics. Then the joint probability distribution of the

n1,n2\ldots,nk

order statistics (with

n1<n2<<nk

and

x1<x2<<xk

) is

\begin{align}

F
X,\ldots,
X
(nk)
(n1)

(x1,\ldots,xk) &=\Pr(

X
(n1)

\leqx1\land

X
(n2)

\leqx2\land\land

X
(nk)

\leqxk)\\ &=

n
\sum
ik=nk
i3
\sum
i2=n2

\sum

i2
i1=n1
P(x1,\ldots,xk)
i1,\ldots,ik
i1!(i2-i1)!(n-ik)!

,\end{align}

where

\begin{align} P
i1,\ldots,ik

(x1,\ldots,xk)=\operatorname{per} \begin{bmatrix} F1(x1)F1(x1)&F1(x2)-F1(x1)F1(x2)-F1(x1)&&1-F1(xk)1-F1(xk)\\ F2(x1)F2(x1)&F2(x2)-F2(x1)F2(x2)-F2(x1)&&1-F2(xk)1-F1(xk)\\ \vdots&\vdots&&\vdots\\ \underbrace{Fn(x1)Fn(x1)

}
i1

&\underbrace{Fn(x2)-Fn(x1)Fn(x2)-Fn(x1)}

i2-i1

&&\underbrace{1-Fn(xk)1-Fn(xk)

}
n-ik

\end{bmatrix} \end{align}

is the permanent of the given block matrix. (The figures under the braces show the number of columns.)

Independent identically distributed case

In the case when the variables

X1,X2,\ldots,Xn

are independent and identically distributed with cumulative probability distribution function

Fi=F

for all i the theorem reduces to
\begin{align} F
X,\ldots,
X
(nk)
(n1)

(x1,\ldots,xk) =

n
\sum
ik=nk

i3
\sum
i2=n2
i2
\sum
i1=n1

n!

i1
F(x
1)
i1!
n-ik
(1-F(x
k))
(n-ik)!
k
\prod\limits
j=2
\left[F(xj)-F(xj-1)
ij-ij-1
\right]
(ij-ij-1)!

. \end{align}

Remarks

Complexity

Glueck et al. note that the Bapat‒Beg formula is computationally intractable, because it involves an exponential number of permanents of the size of the number of random variables.[3] However, when the random variables have only two possible distributions, the complexity can be reduced to

O(m2k)

. Thus, in the case of two populations, the complexity is polynomial in

m

for any fixed number of statistics

k

.

References

  1. R. B. . Bapat . M. I. . Beg . 1989 . Order Statistics for Nonidentically Distributed Variables and Permanents . Sankhyā: The Indian Journal of Statistics, Series A (1961–2002) . 51 . 1 . 79–93 . 25050725 . 1065561.
  2. Sayaji . Hande . 1994 . A Note on Order Statistics for Nondentically Distributed Variables . Sankhyā: The Indian Journal of Statistics, Series A (1961–2002) . 56 . 2 . 365–368 . 25050995 . 1664921.
  3. Glueck. Anis Karimpour-Fard. Jan Mandel. Larry Hunter. Muller. Fast computation by block permanents of cumulative distribution functions of order statistics from several populations. 10.1080/03610920802001896. 2008. Communications in Statistics – Theory and Methods. 37. 18. 2815–2824. 19865590. 2768298. 0705.3851.