Banach space explained

In mathematics, more specifically in functional analysis, a Banach space (pronounced pronounced as /pl/) is a complete normed vector space. Thus, a Banach space is a vector space with a metric that allows the computation of vector length and distance between vectors and is complete in the sense that a Cauchy sequence of vectors always converges to a well-defined limit that is within the space.

Banach spaces are named after the Polish mathematician Stefan Banach, who introduced this concept and studied it systematically in 1920–1922 along with Hans Hahn and Eduard Helly. Maurice René Fréchet was the first to use the term "Banach space" and Banach in turn then coined the term "Fréchet space".Banach spaces originally grew out of the study of function spaces by Hilbert, Fréchet, and Riesz earlier in the century. Banach spaces play a central role in functional analysis. In other areas of analysis, the spaces under study are often Banach spaces.

Definition

(X,\|\|).

A normed space is a pair[1]

(X,\|\|)

consisting of a vector space

X

over a scalar field

K

(where

K

is commonly

\Reals

or

\Complex

) together with a distinguished[2] norm

\|\|:X\to\Reals.

Like all norms, this norm induces a translation invariant[3] distance function, called the canonical or (norm) induced metric, defined for all vectors

x,y\inX

by[4] d(x, y) := \|y - x\| = \|x - y\|.This makes

X

into a metric space

(X,d).

A sequence

x1,x2,\ldots

is called or or if for every real

r>0,

there exists some index

N

such thatd\left(x_n, x_m\right) = \left\|x_n - x_m\right\| < rwhenever

m

and

n

are greater than

N.

The normed space

(X,\|\|)

is called a and the canonical metric

d

is called a if

(X,d)

is a, which by definition means for every Cauchy sequence

x1,x2,\ldots

in

(X,d),

there exists some

x\inX

such that\lim_ x_n = x \; \text (X, d)where because

\left\|xn-x\right\|=d\left(xn,x\right),

this sequence's convergence to

x

can equivalently be expressed as:\lim_ \left\|x_n - x\right\| = 0 \; \text \Reals.

The norm

\|\|

of a normed space

(X,\|\|)

is called a if

(X,\|\|)

is a Banach space.

L-semi-inner product

For any normed space

(X,\|\|),

there exists an L-semi-inner product

\langle,\rangle

on

X

such that \|x\| = \sqrt for all

x\inX

; in general, there may be infinitely many L-semi-inner products that satisfy this condition. L-semi-inner products are a generalization of inner products, which are what fundamentally distinguish Hilbert spaces from all other Banach spaces. This shows that all normed spaces (and hence all Banach spaces) can be considered as being generalizations of (pre-)Hilbert spaces.

Characterization in terms of series

The vector space structure allows one to relate the behavior of Cauchy sequences to that of converging series of vectors. A normed space

X

is a Banach space if and only if each absolutely convergent series in

X

converges in

X,

[5] \sum_^ \|v_n\| < \infty \quad \text \quad \sum_^ v_n\ \ \text \ \ X.

Topology

The canonical metric

d

of a normed space

(X,\|\|)

induces the usual metric topology

\taud

on

X,

which is referred to as the canonical or norm induced topology. Every normed space is automatically assumed to carry this Hausdorff topology, unless indicated otherwise. With this topology, every Banach space is a Baire space, although there exist normed spaces that are Baire but not Banach. The norm

\|\|:\left(X,\taud\right)\to\R

is always a continuous function with respect to the topology that it induces.

The open and closed balls of radius

r>0

centered at a point

x\inX

are, respectively, the sets B_r(x) := \ \qquad \text \qquad C_r(x) := \. Any such ball is a convex and bounded subset of

X,

but a compact ball/neighborhood exists if and only if

X

is a finite-dimensional vector space. In particular, no infinite–dimensional normed space can be locally compact or have the Heine–Borel property. If

x0

is a vector and

s0

is a scalar then x_0 + s B_r(x) = B_
r
\left(x_0 + s x\right) \qquad \text \qquad x_0 + s C_r(x) = C_
r
\left(x_0 + s x\right). Using

s:=1

shows that this norm-induced topology is translation invariant, which means that for any

x\inX

and

S\subseteqX,

the subset

S

is open (respectively, closed) in

X

if and only if this is true of its translation

x+S:=\{x+s:s\inS\}.

Consequently, the norm induced topology is completely determined by any neighbourhood basis at the origin. Some common neighborhood bases at the origin include:\left\, \qquad \left\, \qquad \left\, \qquad \text \qquad \left\where

r1,r2,\ldots

is a sequence in of positive real numbers that converges to

0

in

\R

(such as

rn:=1/n

or

rn:=1/2n

for instance). So for example, every open subset

U

of

X

can be written as a union U = \bigcup_ B_(x) = \bigcup_ x + B_(0) = \bigcup_ x + r_x B_1(0)indexed by some subset

I\subseteqU,

where every

rx

may be picked from the aforementioned sequence

r1,r2,\ldots

(the open balls can be replaced with closed balls, although then the indexing set

I

and radii

rx

may also need to be replaced). Additionally,

I

can always be chosen to be countable if

X

is a, which by definition means that

X

contains some countable dense subset.

Homeomorphism classes of separable Banach spaces

\|\|2.

The Anderson–Kadec theorem states that every infinite–dimensional separable Fréchet space is homeomorphic to the product space \prod_ \Reals of countably many copies of

\Reals

(this homeomorphism need not be a linear map). Thus all infinite–dimensional separable Fréchet spaces are homeomorphic to each other (or said differently, their topology is unique up to a homeomorphism). Since every Banach space is a Fréchet space, this is also true of all infinite–dimensional separable Banach spaces, including

\ell2(\N).

In fact,

\ell2(\N)

is even homeomorphic to its own unit

\left\{x\in\ell2(\N):\|x\|2=1\right\},

which stands in sharp contrast to finite–dimensional spaces (the Euclidean plane

\Reals2

is not homeomorphic to the unit circle, for instance).

This pattern in homeomorphism classes extends to generalizations of metrizable (locally Euclidean) topological manifolds known as, which are metric spaces that are around every point, locally homeomorphic to some open subset of a given Banach space (metric Hilbert manifolds and metric Fréchet manifolds are defined similarly). For example, every open subset

U

of a Banach space

X

is canonically a metric Banach manifold modeled on

X

since the inclusion map

U\toX

is an open local homeomorphism. Using Hilbert space microbundles, David Henderson showed in 1969 that every metric manifold modeled on a separable infinite–dimensional Banach (or Fréchet) space can be topologically embedded as an subset of

\ell2(\N)

and, consequently, also admits a unique smooth structure making it into a

Cinfty

Hilbert manifold.

Compact and convex subsets

There is a compact subset

S

of

\ell2(\N)

whose convex hull

\operatorname{co}(S)

is closed and thus also compact (see this footnote[6] for an example). However, like in all Banach spaces, the convex hull

\overline{\operatorname{co}}S

of this (and every other) compact subset will be compact. But if a normed space is not complete then it is in general guaranteed that

\overline{\operatorname{co}}S

will be compact whenever

S

is; an example can even be found in a (non-complete) pre-Hilbert vector subspace of

\ell2(\N).

As a topological vector space

This norm-induced topology also makes

\left(X,\taud\right)

into what is known as a topological vector space (TVS), which by definition is a vector space endowed with a topology making the operations of addition and scalar multiplication continuous. It is emphasized that the TVS

\left(X,\taud\right)

is a vector space together with a certain type of topology; that is to say, when considered as a TVS, it is associated with particular norm or metric (both of which are "forgotten"). This Hausdorff TVS

\left(X,\taud\right)

is even locally convex because the set of all open balls centered at the origin forms a neighbourhood basis at the origin consisting of convex balanced open sets. This TVS is also, which by definition refers to any TVS whose topology is induced by some (possibly unknown) norm. Normable TVSs are characterized by being Hausdorff and having a bounded convex neighborhood of the origin. All Banach spaces are barrelled spaces, which means that every barrel is neighborhood of the origin (all closed balls centered at the origin are barrels, for example) and guarantees that the Banach–Steinhaus theorem holds.

Comparison of complete metrizable vector topologies

The open mapping theorem implies that if

\tau

and

\tau2

are topologies on

X

that make both

(X,\tau)

and

\left(X,\tau2\right)

into complete metrizable TVS (for example, Banach or Fréchet spaces) and if one topology is finer or coarser than the other then they must be equal (that is, if

\tau\subseteq\tau2

or

\tau2\subseteq\tau

then

\tau=\tau2

).So for example, if

(X,p)

and

(X,q)

are Banach spaces with topologies

\taup

and

\tauq

and if one of these spaces has some open ball that is also an open subset of the other space (or equivalently, if one of

p:\left(X,\tauq\right)\to\Reals

or

q:\left(X,\taup\right)\to\Reals

is continuous) then their topologies are identical and their norms are equivalent.

Completeness

Complete norms and equivalent norms

Two norms,

p

and

q,

on a vector space

X

are said to be if they induce the same topology;[7] this happens if and only if there exist positive real numbers

c,C>0

such that c q(x) \leq p(x) \leq C q(x) for all

x\inX.

If

p

and

q

are two equivalent norms on a vector space

X

then

(X,p)

is a Banach space if and only if

(X,q)

is a Banach space. See this footnote for an example of a continuous norm on a Banach space that is equivalent to that Banach space's given norm.[8] [7] All norms on a finite-dimensional vector space are equivalent and every finite-dimensional normed space is a Banach space.[9]

Complete norms vs complete metrics

A metric

D

on a vector space

X

is induced by a norm on

X

if and only if

D

is translation invariant[3] and , which means that

D(sx,sy)=|s|D(x,y)

for all scalars

s

and all

x,y\inX,

in which case the function

\|x\|:=D(x,0)

defines a norm on

X

and the canonical metric induced by

\|\|

is equal to

D.

Suppose that

(X,\|\|)

is a normed space and that

\tau

is the norm topology induced on

X.

Suppose that

D

is metric on

X

such that the topology that

D

induces on

X

is equal to

\tau.

If

D

is translation invariant[3] then

(X,\|\|)

is a Banach space if and only if

(X,D)

is a complete metric space. If

D

is translation invariant, then it may be possible for

(X,\|\|)

to be a Banach space but for

(X,D)

to be a complete metric space (see this footnote[10] for an example). In contrast, a theorem of Klee,[11] [12] which also applies to all metrizable topological vector spaces, implies that if there exists [13] complete metric

D

on

X

that induces the norm topology

\tau

on

X,

then

(X,\|\|)

is a Banach space.

Cinfty(K),

whose definition can be found in the article on spaces of test functions and distributions.

Complete norms vs complete topological vector spaces

There is another notion of completeness besides metric completeness and that is the notion of a complete topological vector space (TVS) or TVS-completeness, which uses the theory of uniform spaces. Specifically, the notion of TVS-completeness uses a unique translation-invariant uniformity, called the canonical uniformity, that depends on vector subtraction and the topology

\tau

that the vector space is endowed with, and so in particular, this notion of TVS completeness is independent of whatever norm induced the topology

\tau

(and even applies to TVSs that are even metrizable). Every Banach space is a complete TVS. Moreover, a normed space is a Banach space (that is, its norm-induced metric is complete) if and only if it is complete as a topological vector space. If

(X,\tau)

is a metrizable topological vector space (such as any norm induced topology, for example), then

(X,\tau)

is a complete TVS if and only if it is a complete TVS, meaning that it is enough to check that every Cauchy in

(X,\tau)

converges in

(X,\tau)

to some point of

X

(that is, there is no need to consider the more general notion of arbitrary Cauchy nets).

If

(X,\tau)

is a topological vector space whose topology is induced by (possibly unknown) norm (such spaces are called), then

(X,\tau)

is a complete topological vector space if and only if

X

may be assigned a norm

\|\|

that induces on

X

the topology

\tau

and also makes

(X,\|\|)

into a Banach space. A Hausdorff locally convex topological vector space

X

is normable if and only if its strong dual space
\prime
X
b
is normable, in which case
\prime
X
b
is a Banach space (
\prime
X
b
denotes the strong dual space of

X,

whose topology is a generalization of the dual norm-induced topology on the continuous dual space

X\prime

; see this footnote[15] for more details). If

X

is a metrizable locally convex TVS, then

X

is normable if and only if
\prime
X
b
is a Fréchet–Urysohn space.[16] This shows that in the category of locally convex TVSs, Banach spaces are exactly those complete spaces that are both metrizable and have metrizable strong dual spaces.

Completions

Every normed space can be isometrically embedded onto a dense vector subspace of Banach space, where this Banach space is called a of the normed space. This Hausdorff completion is unique up to isometric isomorphism.

More precisely, for every normed space

X,

there exist a Banach space

Y

and a mapping

T:X\toY

such that

T

is an isometric mapping and

T(X)

is dense in

Y.

If

Z

is another Banach space such that there is an isometric isomorphism from

X

onto a dense subset of

Z,

then

Z

is isometrically isomorphic to

Y.

This Banach space

Y

is the Hausdorff of the normed space

X.

The underlying metric space for

Y

is the same as the metric completion of

X,

with the vector space operations extended from

X

to

Y.

The completion of

X

is sometimes denoted by

\widehat{X}.

General theory

Linear operators, isomorphisms

See main article: Bounded operator. If

X

and

Y

are normed spaces over the same ground field

K,

the set of all continuous

K

-linear maps

T:X\toY

is denoted by

B(X,Y).

In infinite-dimensional spaces, not all linear maps are continuous. A linear mapping from a normed space

X

to another normed space is continuous if and only if it is bounded on the closed unit ball of

X.

Thus, the vector space

B(X,Y)

can be given the operator norm\|T\| = \sup \left\.

For

Y

a Banach space, the space

B(X,Y)

is a Banach space with respect to this norm. In categorical contexts, it is sometimes convenient to restrict the function space between two Banach spaces to only the short maps; in that case the space

B(X,Y)

reappears as a natural bifunctor.[17]

If

X

is a Banach space, the space

B(X)=B(X,X)

forms a unital Banach algebra; the multiplication operation is given by the composition of linear maps.

If

X

and

Y

are normed spaces, they are isomorphic normed spaces if there exists a linear bijection

T:X\toY

such that

T

and its inverse

T-1

are continuous. If one of the two spaces

X

or

Y

is complete (or reflexive, separable, etc.) then so is the other space. Two normed spaces

X

and

Y

are isometrically isomorphic if in addition,

T

is an isometry, that is,

\|T(x)\|=\|x\|

for every

x

in

X.

The Banach–Mazur distance

d(X,Y)

between two isomorphic but not isometric spaces

X

and

Y

gives a measure of how much the two spaces

X

and

Y

differ.

Continuous and bounded linear functions and seminorms

Every continuous linear operator is a bounded linear operator and if dealing only with normed spaces then the converse is also true. That is, a linear operator between two normed spaces is bounded if and only if it is a continuous function. So in particular, because the scalar field (which is

\R

or

\Complex

) is a normed space, a linear functional on a normed space is a bounded linear functional if and only if it is a continuous linear functional. This allows for continuity-related results (like those below) to be applied to Banach spaces. Although boundedness is the same as continuity for linear maps between normed spaces, the term "bounded" is more commonly used when dealing primarily with Banach spaces.

If

f:X\to\R

is a subadditive function (such as a norm, a sublinear function, or real linear functional), then

f

is continuous at the origin if and only if

f

is uniformly continuous on all of

X

; and if in addition

f(0)=0

then

f

is continuous if and only if its absolute value

|f|:X\to[0,infty)

is continuous, which happens if and only if

\{x\inX:|f(x)|<1\}

is an open subset of

X.

[18] And very importantly for applying the Hahn–Banach theorem, a linear functional

f

is continuous if and only if this is true of its real part

\operatorname{Re}f

and moreover,

\|\operatorname{Re}f\|=\|f\|

and the real part

\operatorname{Re}f

completely determines

f,

which is why the Hahn–Banach theorem is often stated only for real linear functionals.Also, a linear functional

f

on

X

is continuous if and only if the seminorm

|f|

is continuous, which happens if and only if there exists a continuous seminorm

p:X\to\R

such that

|f|\leqp

; this last statement involving the linear functional

f

and seminorm

p

is encountered in many versions of the Hahn–Banach theorem.

Basic notions

The Cartesian product

X x Y

of two normed spaces is not canonically equipped with a norm. However, several equivalent norms are commonly used, such as\|(x, y)\|_1 = \|x\| + \|y\|, \qquad \|(x, y)\|_\infty = \max (\|x\|, \|y\|)which correspond (respectively) to the coproduct and product in the category of Banach spaces and short maps (discussed above). For finite (co)products, these norms give rise to isomorphic normed spaces, and the product

X x Y

(or the direct sum

XY

) is complete if and only if the two factors are complete.

If

M

is a closed linear subspace of a normed space

X,

there is a natural norm on the quotient space

X/M,

\|x + M\| = \inf\limits_ \|x + m\|.

The quotient

X/M

is a Banach space when

X

is complete.[19] The quotient map from

X

onto

X/M,

sending

x\inX

to its class

x+M,

is linear, onto and has norm

1,

except when

M=X,

in which case the quotient is the null space.

The closed linear subspace

M

of

X

is said to be a complemented subspace of

X

if

M

is the range of a surjective bounded linear projection

P:X\toM.

In this case, the space

X

is isomorphic to the direct sum of

M

and

\kerP,

the kernel of the projection

P.

Suppose that

X

and

Y

are Banach spaces and that

T\inB(X,Y).

There exists a canonical factorization of

T

asT = T_1 \circ \pi, \ \ \ T : X \ \overset\ X / \ker(T) \ \overset \ Ywhere the first map

\pi

is the quotient map, and the second map

T1

sends every class

x+\kerT

in the quotient to the image

T(x)

in

Y.

This is well defined because all elements in the same class have the same image. The mapping

T1

is a linear bijection from

X/\kerT

onto the range

T(X),

whose inverse need not be bounded.

Classical spaces

Basic examples[20] of Banach spaces include: the Lp spaces

Lp

and their special cases, the sequence spaces

\ellp

that consist of scalar sequences indexed by natural numbers

\N

; among them, the space

\ell1

of absolutely summable sequences and the space

\ell2

of square summable sequences; the space

c0

of sequences tending to zero and the space

\ellinfty

of bounded sequences; the space

C(K)

of continuous scalar functions on a compact Hausdorff space

K,

equipped with the max norm,\|f\|_ = \max \, \quad f \in C(K).

According to the Banach–Mazur theorem, every Banach space is isometrically isomorphic to a subspace of some

C(K).

[21] For every separable Banach space

X,

there is a closed subspace

M

of

\ell1

such that

X:=\ell1/M.

[22]

Any Hilbert space serves as an example of a Banach space. A Hilbert space

H

on

K=\Reals,\Complex

is complete for a norm of the form\|x\|_H = \sqrt,where\langle \cdot, \cdot \rangle : H \times H \to \mathbbis the inner product, linear in its first argument that satisfies the following:\begin\langle y, x \rangle &= \overline, \quad \text x, y \in H \\\langle x, x \rangle & \geq 0, \quad \text x \in H \\\langle x,x \rangle = 0 \text x &= 0.\end

For example, the space

L2

is a Hilbert space.

The Hardy spaces, the Sobolev spaces are examples of Banach spaces that are related to

Lp

spaces and have additional structure. They are important in different branches of analysis, Harmonic analysis and Partial differential equations among others.

Banach algebras

A Banach algebra is a Banach space

A

over

K=\R

or

\Complex,

together with a structure of algebra over

K

, such that the product map

A x A\ni(a,b)\mapstoab\inA

is continuous. An equivalent norm on

A

can be found so that

\|ab\|\leq\|a\|\|b\|

for all

a,b\inA.

Examples

C(K)

with the pointwise product, is a Banach algebra.

A(D)

consists of functions holomorphic in the open unit disk

D\subseteq\Complex

and continuous on its closure:

\overline{D

}. Equipped with the max norm on

\overline{D

}, the disk algebra

A(D)

is a closed subalgebra of

C\left(\overline{D

}\right).

A(T)

is the algebra of functions on the unit circle

T

with absolutely convergent Fourier series. Via the map associating a function on

T

to the sequence of its Fourier coefficients, this algebra is isomorphic to the Banach algebra

\ell1(Z),

where the product is the convolution of sequences.

X,

the space

B(X)

of bounded linear operators on

X,

with the composition of maps as product, is a Banach algebra.

A

with an antilinear involution

a\mapstoa*

such that

\left\|a*a\right\|=\|a\|2.

The space

B(H)

of bounded linear operators on a Hilbert space

H

is a fundamental example of C*-algebra. The Gelfand–Naimark theorem states that every C*-algebra is isometrically isomorphic to a C*-subalgebra of some

B(H).

The space

C(K)

of complex continuous functions on a compact Hausdorff space

K

is an example of commutative C*-algebra, where the involution associates to every function

f

its complex conjugate

\overline{f}.

Dual space

See main article: Dual space. If

X

is a normed space and

K

the underlying field (either the real or the complex numbers), the continuous dual space is the space of continuous linear maps from

X

into

K,

or continuous linear functionals. The notation for the continuous dual is

X\prime=B(X,K)

in this article.[23] Since

K

is a Banach space (using the absolute value as norm), the dual

X\prime

is a Banach space, for every normed space

X.

The Dixmier–Ng theorem characterizes the dual spaces of Banach spaces.

The main tool for proving the existence of continuous linear functionals is the Hahn–Banach theorem.

In particular, every continuous linear functional on a subspace of a normed space can be continuously extended to the whole space, without increasing the norm of the functional.[24] An important special case is the following: for every vector

x

in a normed space

X,

there exists a continuous linear functional

f

on

X

such thatf(x) = \|x\|_X, \quad \|f\|_ \leq 1.

When

x

is not equal to the

0

vector, the functional

f

must have norm one, and is called a norming functional for

x.

The Hahn–Banach separation theorem states that two disjoint non-empty convex sets in a real Banach space, one of them open, can be separated by a closed affine hyperplane. The open convex set lies strictly on one side of the hyperplane, the second convex set lies on the other side but may touch the hyperplane.[25]

A subset

S

in a Banach space

X

is total if the linear span of

S

is dense in

X.

The subset

S

is total in

X

if and only if the only continuous linear functional that vanishes on

S

is the

0

functional: this equivalence follows from the Hahn–Banach theorem.

If

X

is the direct sum of two closed linear subspaces

M

and

N,

then the dual

X\prime

of

X

is isomorphic to the direct sum of the duals of

M

and

N.

[26] If

M

is a closed linear subspace in

X,

one can associate the

M

in the dual,M^ = \left\.

The orthogonal

M\bot

is a closed linear subspace of the dual. The dual of

M

is isometrically isomorphic to

X'/M\bot.

The dual of

X/M

is isometrically isomorphic to

M\bot.

[27]

The dual of a separable Banach space need not be separable, but:

When

X'

is separable, the above criterion for totality can be used for proving the existence of a countable total subset in

X.

Weak topologies

The weak topology on a Banach space

X

is the coarsest topology on

X

for which all elements

x\prime

in the continuous dual space

X\prime

are continuous. The norm topology is therefore finer than the weak topology. It follows from the Hahn–Banach separation theorem that the weak topology is Hausdorff, and that a norm-closed convex subset of a Banach space is also weakly closed.[28] A norm-continuous linear map between two Banach spaces

X

and

Y

is also weakly continuous, that is, continuous from the weak topology of

X

to that of

Y.

[29]

If

X

is infinite-dimensional, there exist linear maps which are not continuous. The space

X*

of all linear maps from

X

to the underlying field

K

(this space

X*

is called the algebraic dual space, to distinguish it from

X\prime

also induces a topology on

X

which is finer than the weak topology, and much less used in functional analysis.

On a dual space

X\prime,

there is a topology weaker than the weak topology of

X\prime,

called weak* topology. It is the coarsest topology on

X\prime

for which all evaluation maps

x\prime\inX\prime\mapstox\prime(x),

where

x

ranges over

X,

are continuous. Its importance comes from the Banach–Alaoglu theorem.

The Banach–Alaoglu theorem can be proved using Tychonoff's theorem about infinite products of compact Hausdorff spaces. When

X

is separable, the unit ball

B\prime

of the dual is a metrizable compact in the weak* topology.[30]

Examples of dual spaces

The dual of

c0

is isometrically isomorphic to

\ell1

: for every bounded linear functional

f

on

c0,

there is a unique element

y=\left\{yn\right\}\in\ell1

such thatf(x) = \sum_ x_n y_n, \qquad x = \ \in c_0, \ \ \text \ \ \|f\|_ = \|y\|_.

The dual of

\ell1

is isometrically isomorphic to

\ellinfty

. The dual of Lebesgue space

Lp([0,1])

is isometrically isomorphic to

Lq([0,1])

when

1\leqp<infty

and
1
p

+

1
q

=1.

For every vector

y

in a Hilbert space

H,

the mappingx \in H \to f_y(x) = \langle x, y \rangle

defines a continuous linear functional

fy

on

H.

The Riesz representation theorem states that every continuous linear functional on

H

is of the form

fy

for a uniquely defined vector

y

in

H.

The mapping

y\inH\tofy

is an antilinear isometric bijection from

H

onto its dual

H'.

When the scalars are real, this map is an isometric isomorphism.

When

K

is a compact Hausdorff topological space, the dual

M(K)

of

C(K)

is the space of Radon measures in the sense of Bourbaki.[31] The subset

P(K)

of

M(K)

consisting of non-negative measures of mass 1 (probability measures) is a convex w*-closed subset of the unit ball of

M(K).

The extreme points of

P(K)

are the Dirac measures on

K.

The set of Dirac measures on

K,

equipped with the w*-topology, is homeomorphic to

K.

The result has been extended by Amir[32] and Cambern[33] to the case when the multiplicative Banach–Mazur distance between

C(K)

and

C(L)

is

<2.

The theorem is no longer true when the distance is

=2.

[34]

C(K),

the maximal ideals are precisely kernels of Dirac measures on

K,

I_x = \ker \delta_x = \, \quad x \in K.

More generally, by the Gelfand–Mazur theorem, the maximal ideals of a unital commutative Banach algebra can be identified with its characters—not merely as sets but as topological spaces: the former with the hull-kernel topology and the latter with the w*-topology. In this identification, the maximal ideal space can be viewed as a w*-compact subset of the unit ball in the dual

A'.

Not every unital commutative Banach algebra is of the form

C(K)

for some compact Hausdorff space

K.

However, this statement holds if one places

C(K)

in the smaller category of commutative C*-algebras. Gelfand's representation theorem for commutative C*-algebras states that every commutative unital C*-algebra

A

is isometrically isomorphic to a

C(K)

space.[35] The Hausdorff compact space

K

here is again the maximal ideal space, also called the spectrum of

A

in the C*-algebra context.

Bidual

See also: Reflexive space and Semi-reflexive space.

If

X

is a normed space, the (continuous) dual

X''

of the dual

X'

is called , or of

X.

For every normed space

X,

there is a natural map,This defines

FX(x)

as a continuous linear functional on

X\prime,

that is, an element of

X\prime\prime.

The map

FX\colonx\toFX(x)

is a linear map from

X

to

X\prime\prime.

As a consequence of the existence of a norming functional

f

for every

x\inX,

this map

FX

is isometric, thus injective.

For example, the dual of

X=c0

is identified with

\ell1,

and the dual of

\ell1

is identified with

\ellinfty,

the space of bounded scalar sequences. Under these identifications,

FX

is the inclusion map from

c0

to

\ellinfty.

It is indeed isometric, but not onto.

If

FX

is surjective, then the normed space

X

is called reflexive (see below). Being the dual of a normed space, the bidual

X''

is complete, therefore, every reflexive normed space is a Banach space.

Using the isometric embedding

FX,

it is customary to consider a normed space

X

as a subset of its bidual. When

X

is a Banach space, it is viewed as a closed linear subspace of

X\prime\prime.

If

X

is not reflexive, the unit ball of

X

is a proper subset of the unit ball of

X\prime\prime.

The Goldstine theorem states that the unit ball of a normed space is weakly*-dense in the unit ball of the bidual. In other words, for every

x''

in the bidual, there exists a net

\left(xi\right)i

in

X

so thatThe net may be replaced by a weakly*-convergent sequence when the dual

X'

is separable. On the other hand, elements of the bidual of

\ell1

that are not in

\ell1

cannot be weak*-limit of in

\ell1,

since

\ell1

is weakly sequentially complete.

Banach's theorems

Here are the main general results about Banach spaces that go back to the time of Banach's book and are related to the Baire category theorem. According to this theorem, a complete metric space (such as a Banach space, a Fréchet space or an F-space) cannot be equal to a union of countably many closed subsets with empty interiors. Therefore, a Banach space cannot be the union of countably many closed subspaces, unless it is already equal to one of them; a Banach space with a countable Hamel basis is finite-dimensional.

The Banach–Steinhaus theorem is not limited to Banach spaces. It can be extended for example to the case where

X

is a Fréchet space, provided the conclusion is modified as follows: under the same hypothesis, there exists a neighborhood

U

of

0

in

X

such that all

T

in

F

are uniformly bounded on

U,

\sup_ \sup_ \; \|T(x)\|_Y < \infty.

This result is a direct consequence of the preceding Banach isomorphism theorem and of the canonical factorization of bounded linear maps.

This is another consequence of Banach's isomorphism theorem, applied to the continuous bijection from

M1Mn

onto

X

sending

m1,,mn

to the sum

m1++mn.

Reflexivity

See main article: Reflexive space.

The normed space

X

is called reflexive when the natural map\begin F_X : X \to X \\ F_X(x) (f) = f(x) & \text x \in X, \text f \in X'\endis surjective. Reflexive normed spaces are Banach spaces.

This is a consequence of the Hahn–Banach theorem. Further, by the open mapping theorem, if there is a bounded linear operator from the Banach space

X

onto the Banach space

Y,

then

Y

is reflexive.

Indeed, if the dual

Y\prime

of a Banach space

Y

is separable, then

Y

is separable. If

X

is reflexive and separable, then the dual of

X\prime

is separable, so

X\prime

is separable.

Hilbert spaces are reflexive. The

Lp

spaces are reflexive when

1<p<infty.

More generally, uniformly convex spaces are reflexive, by the Milman–Pettis theorem. The spaces

c0,\ell1,L1([0,1]),C([0,1])

are not reflexive. In these examples of non-reflexive spaces

X,

the bidual

X''

is "much larger" than

X.

Namely, under the natural isometric embedding of

X

into

X''

given by the Hahn–Banach theorem, the quotient

X\prime\prime/X

is infinite-dimensional, and even nonseparable. However, Robert C. James has constructed an example[36] of a non-reflexive space, usually called "the James space" and denoted by

J,

[37] such that the quotient

J\prime\prime/J

is one-dimensional. Furthermore, this space

J

is isometrically isomorphic to its bidual.

When

X

is reflexive, it follows that all closed and bounded convex subsets of

X

are weakly compact. In a Hilbert space

H,

the weak compactness of the unit ball is very often used in the following way: every bounded sequence in

H

has weakly convergent subsequences.

Weak compactness of the unit ball provides a tool for finding solutions in reflexive spaces to certain optimization problems. For example, every convex continuous function on the unit ball

B

of a reflexive space attains its minimum at some point in

B.

As a special case of the preceding result, when

X

is a reflexive space over

\R,

every continuous linear functional

f

in

X\prime

attains its maximum

\|f\|

on the unit ball of

X.

The following theorem of Robert C. James provides a converse statement.

The theorem can be extended to give a characterization of weakly compact convex sets.

On every non-reflexive Banach space

X,

there exist continuous linear functionals that are not norm-attaining. However, the BishopPhelps theorem[38] states that norm-attaining functionals are norm dense in the dual

X\prime

of

X.

Weak convergences of sequences

A sequence

\left\{xn\right\}

in a Banach space

X

is weakly convergent to a vector

x\inX

if

\left\{f\left(xn\right)\right\}

converges to

f(x)

for every continuous linear functional

f

in the dual

X\prime.

The sequence

\left\{xn\right\}

is a weakly Cauchy sequence if

\left\{f\left(xn\right)\right\}

converges to a scalar limit

L(f),,

for every

f

in

X\prime.

A sequence

\left\{fn\right\}

in the dual

X\prime

is weakly* convergent to a functional

f\inX\prime

if

fn(x)

converges to

f(x)

for every

x

in

X.

Weakly Cauchy sequences, weakly convergent and weakly* convergent sequences are norm bounded, as a consequence of the Banach–Steinhaus theorem.

When the sequence

\left\{xn\right\}

in

X

is a weakly Cauchy sequence, the limit

L

above defines a bounded linear functional on the dual

X\prime,

that is, an element

L

of the bidual of

X,

and

L

is the limit of

\left\{xn\right\}

in the weak*-topology of the bidual. The Banach space

X

is weakly sequentially complete if every weakly Cauchy sequence is weakly convergent in

X.

It follows from the preceding discussion that reflexive spaces are weakly sequentially complete.

An orthonormal sequence in a Hilbert space is a simple example of a weakly convergent sequence, with limit equal to the

0

vector. The unit vector basis of

\ellp

for

1<p<infty,

or of

c0,

is another example of a weakly null sequence, that is, a sequence that converges weakly to

0.

For every weakly null sequence in a Banach space, there exists a sequence of convex combinations of vectors from the given sequence that is norm-converging to

0.

[39]

The unit vector basis of

\ell1

is not weakly Cauchy. Weakly Cauchy sequences in

\ell1

are weakly convergent, since

L1

-spaces are weakly sequentially complete. Actually, weakly convergent sequences in

\ell1

are norm convergent.[40] This means that

\ell1

satisfies Schur's property.

Results involving the

\ell1

basis

Weakly Cauchy sequences and the

\ell1

basis are the opposite cases of the dichotomy established in the following deep result of H. P. Rosenthal.[41]

A complement to this result is due to Odell and Rosenthal (1975).

By the Goldstine theorem, every element of the unit ball

B\prime\prime

of

X\prime\prime

is weak*-limit of a net in the unit ball of

X.

When

X

does not contain

\ell1,

every element of

B\prime\prime

is weak*-limit of a in the unit ball of

X.

[42]

When the Banach space

X

is separable, the unit ball of the dual

X\prime,

equipped with the weak*-topology, is a metrizable compact space

K,

and every element

x\prime\prime

in the bidual

X\prime\prime

defines a bounded function on

K

:x' \in K \mapsto x(x'), \quad \left |x(x')\right| \leq \left \|x\right \|.

This function is continuous for the compact topology of

K

if and only if

x\prime\prime

is actually in

X,

considered as subset of

X\prime\prime.

Assume in addition for the rest of the paragraph that

X

does not contain

\ell1.

By the preceding result of Odell and Rosenthal, the function

x\prime\prime

is the pointwise limit on

K

of a sequence

\left\{xn\right\}\subseteqX

of continuous functions on

K,

it is therefore a first Baire class function on

K.

The unit ball of the bidual is a pointwise compact subset of the first Baire class on

K.

[43]

Sequences, weak and weak* compactness

When

X

is separable, the unit ball of the dual is weak*-compact by the Banach–Alaoglu theorem and metrizable for the weak* topology, hence every bounded sequence in the dual has weakly* convergent subsequences. This applies to separable reflexive spaces, but more is true in this case, as stated below.

The weak topology of a Banach space

X

is metrizable if and only if

X

is finite-dimensional.[44] If the dual

X'

is separable, the weak topology of the unit ball of

X

is metrizable. This applies in particular to separable reflexive Banach spaces. Although the weak topology of the unit ball is not metrizable in general, one can characterize weak compactness using sequences.

A Banach space

X

is reflexive if and only if each bounded sequence in

X

has a weakly convergent subsequence.[45]

A weakly compact subset

A

in

\ell1

is norm-compact. Indeed, every sequence in

A

has weakly convergent subsequences by Eberlein–Šmulian, that are norm convergent by the Schur property of

\ell1.

Type and cotype

See main article: Type and cotype of a Banach space. A way to classify Banach spaces is through the probabilistic notion of type and cotype, these two measure how far a Banach space is from a Hilbert space.

Schauder bases

See main article: Schauder basis.

A Schauder basis in a Banach space

X

is a sequence

\left\{en\right\}n

of vectors in

X

with the property that for every vector

x\inX,

there exist defined scalars

\left\{xn\right\}n

depending on

x,

such thatx = \sum_^ x_n e_n, \quad \textit \quad x = \lim_n P_n(x), \ P_n(x) := \sum_^n x_k e_k.

Banach spaces with a Schauder basis are necessarily separable, because the countable set of finite linear combinations with rational coefficients (say) is dense.

It follows from the Banach–Steinhaus theorem that the linear mappings

\left\{Pn\right\}

are uniformly bounded by some constant

C.

Let

\left\{

*
e
n

\right\}

denote the coordinate functionals which assign to every

x

in

X

the coordinate

xn

of

x

in the above expansion. They are called biorthogonal functionals. When the basis vectors have norm

1,

the coordinate functionals
*\right\}
\left\{e
n
have norm

\leq2C

in the dual of

X.

\left\{hn\right\}

is a basis for

Lp([0,1]),1\leqp<infty.

The trigonometric system is a basis in

Lp(T)

when

1<p<infty.

The Schauder system is a basis in the space

C([0,1]).

[46] The question of whether the disk algebra

A(D)

has a basis[47] remained open for more than forty years, until Bočkarev showed in 1974 that

A(D)

admits a basis constructed from the Franklin system.[48]

Since every vector

x

in a Banach space

X

with a basis is the limit of

Pn(x),

with

Pn

of finite rank and uniformly bounded, the space

X

satisfies the bounded approximation property. The first example by Enflo of a space failing the approximation property was at the same time the first example of a separable Banach space without a Schauder basis.[49]

Robert C. James characterized reflexivity in Banach spaces with a basis: the space

X

with a Schauder basis is reflexive if and only if the basis is both shrinking and boundedly complete.[50] In this case, the biorthogonal functionals form a basis of the dual of

X.

Tensor product

See main article: Tensor product and Topological tensor product. Let

X

and

Y

be two

K

-vector spaces. The tensor product

XY

of

X

and

Y

is a

K

-vector space

Z

with a bilinear mapping

T:X x Y\toZ

which has the following universal property:

If

T1:X x Y\toZ1

is any bilinear mapping into a

K

-vector space

Z1,

then there exists a unique linear mapping

f:Z\toZ1

such that

T1=f\circT.

The image under

T

of a couple

(x,y)

in

X x Y

is denoted by

xy,

and called a simple tensor. Every element

z

in

XY

is a finite sum of such simple tensors.

There are various norms that can be placed on the tensor product of the underlying vector spaces, amongst others the projective cross norm and injective cross norm introduced by A. Grothendieck in 1955.[51]

In general, the tensor product of complete spaces is not complete again. When working with Banach spaces, it is customary to say that the projective tensor product[52] of two Banach spaces

X

and

Y

is the

X\widehat{}\piY

of the algebraic tensor product

XY

equipped with the projective tensor norm, and similarly for the injective tensor product[53]

X\widehat{}\varepsilonY.

Grothendieck proved in particular that[54]

\beginC(K) \widehat_\varepsilon Y &\simeq C(K, Y), \\L^1([0, 1]) \widehat_\pi Y &\simeq L^1([0, 1], Y),\endwhere

K

is a compact Hausdorff space,

C(K,Y)

the Banach space of continuous functions from

K

to

Y

and

L1([0,1],Y)

the space of Bochner-measurable and integrable functions from

[0,1]

to

Y,

and where the isomorphisms are isometric. The two isomorphisms above are the respective extensions of the map sending the tensor

fy

to the vector-valued function

s\inK\tof(s)y\inY.

Tensor products and the approximation property

Let

X

be a Banach space. The tensor product

X'\widehat\varepsilonX

is identified isometrically with the closure in

B(X)

of the set of finite rank operators. When

X

has the approximation property, this closure coincides with the space of compact operators on

X.

For every Banach space

Y,

there is a natural norm

1

linear mapY \widehat\otimes_\pi X \to Y \widehat\otimes_\varepsilon Xobtained by extending the identity map of the algebraic tensor product. Grothendieck related the approximation problem to the question of whether this map is one-to-one when

Y

is the dual of

X.

Precisely, for every Banach space

X,

the mapX' \widehat \otimes_\pi X \ \longrightarrow X' \widehat \otimes_\varepsilon Xis one-to-one if and only if

X

has the approximation property.[55]

Grothendieck conjectured that

X\widehat{}\piY

and

X\widehat{}\varepsilonY

must be different whenever

X

and

Y

are infinite-dimensional Banach spaces. This was disproved by Gilles Pisier in 1983.[56] Pisier constructed an infinite-dimensional Banach space

X

such that

X\widehat{}\piX

and

X\widehat{}\varepsilonX

are equal. Furthermore, just as Enflo's example, this space

X

is a "hand-made" space that fails to have the approximation property. On the other hand, Szankowski proved that the classical space

B\left(\ell2\right)

does not have the approximation property.[57]

Some classification results

Characterizations of Hilbert space among Banach spaces

A necessary and sufficient condition for the norm of a Banach space

X

to be associated to an inner product is the parallelogram identity:

Lp([0,1])

is a Hilbert space only when

p=2.

If this identity is satisfied, the associated inner product is given by the polarization identity. In the case of real scalars, this gives:\langle x, y\rangle = \tfrac \left(\|x+y\|^2 - \|x-y\|^2 \right).

For complex scalars, defining the inner product so as to be

\Complex

-linear in

x,

antilinear in

y,

the polarization identity gives:\langle x,y\rangle = \tfrac \left(\|x+y\|^2 - \|x-y\|^2 + i \left(\|x+iy\|^2 - \|x-iy\|^2\right)\right).

To see that the parallelogram law is sufficient, one observes in the real case that

\langlex,y\rangle

is symmetric, and in the complex case, that it satisfies the Hermitian symmetry property and

\langleix,y\rangle=i\langlex,y\rangle.

The parallelogram law implies that

\langlex,y\rangle

is additive in

x.

It follows that it is linear over the rationals, thus linear by continuity.

Several characterizations of spaces isomorphic (rather than isometric) to Hilbert spaces are available. The parallelogram law can be extended to more than two vectors, and weakened by the introduction of a two-sided inequality with a constant

c\geq1

: Kwapień proved that ifc^ \sum_^n \left\|x_k\right\|^2 \leq \operatorname_ \left\|\sum_^n \pm x_k\right\|^2 \leq c^2 \sum_^n \left\|x_k\right\|^2for every integer

n

and all families of vectors

\left\{x1,\ldots,xn\right\}\subseteqX,

then the Banach space

X

is isomorphic to a Hilbert space.[58] Here,

\operatorname{Ave}\pm

denotes the average over the

2n

possible choices of signs

\pm1.

In the same article, Kwapień proved that the validity of a Banach-valued Parseval's theorem for the Fourier transform characterizes Banach spaces isomorphic to Hilbert spaces.

Lindenstrauss and Tzafriri proved that a Banach space in which every closed linear subspace is complemented (that is, is the range of a bounded linear projection) is isomorphic to a Hilbert space.[59] The proof rests upon Dvoretzky's theorem about Euclidean sections of high-dimensional centrally symmetric convex bodies. In other words, Dvoretzky's theorem states that for every integer

n,

any finite-dimensional normed space, with dimension sufficiently large compared to

n,

contains subspaces nearly isometric to the

n

-dimensional Euclidean space.

The next result gives the solution of the so-called . An infinite-dimensional Banach space

X

is said to be homogeneous if it is isomorphic to all its infinite-dimensional closed subspaces. A Banach space isomorphic to

\ell2

is homogeneous, and Banach asked for the converse.[60]

An infinite-dimensional Banach space is hereditarily indecomposable when no subspace of it can be isomorphic to the direct sum of two infinite-dimensional Banach spaces. The Gowers dichotomy theorem asserts that every infinite-dimensional Banach space

X

contains, either a subspace

Y

with unconditional basis, or a hereditarily indecomposable subspace

Z,

and in particular,

Z

is not isomorphic to its closed hyperplanes.[61] If

X

is homogeneous, it must therefore have an unconditional basis. It follows then from the partial solution obtained by Komorowski and Tomczak–Jaegermann, for spaces with an unconditional basis,[62] that

X

is isomorphic to

\ell2.

Metric classification

If

T:X\toY

is an isometry from the Banach space

X

onto the Banach space

Y

(where both

X

and

Y

are vector spaces over

\R

), then the Mazur–Ulam theorem states that

T

must be an affine transformation. In particular, if

T(0X)=0Y,

this is

T

maps the zero of

X

to the zero of

Y,

then

T

must be linear. This result implies that the metric in Banach spaces, and more generally in normed spaces, completely captures their linear structure.

Topological classification

Finite dimensional Banach spaces are homeomorphic as topological spaces, if and only if they have the same dimension as real vector spaces.

Anderson–Kadec theorem (1965–66) proves[63] that any two infinite-dimensional separable Banach spaces are homeomorphic as topological spaces. Kadec's theorem was extended by Torunczyk, who proved[64] that any two Banach spaces are homeomorphic if and only if they have the same density character, the minimum cardinality of a dense subset.

Spaces of continuous functions

When two compact Hausdorff spaces

K1

and

K2

are homeomorphic, the Banach spaces

C\left(K1\right)

and

C\left(K2\right)

are isometric. Conversely, when

K1

is not homeomorphic to

K2,

the (multiplicative) Banach–Mazur distance between

C\left(K1\right)

and

C\left(K2\right)

must be greater than or equal to

2,

see above the results by Amir and Cambern. Although uncountable compact metric spaces can have different homeomorphy types, one has the following result due to Milutin:[65]

The situation is different for countably infinite compact Hausdorff spaces. Every countably infinite compact

K

is homeomorphic to some closed interval of ordinal numbers\langle 1, \alpha \rangle = \equipped with the order topology, where

\alpha

is a countably infinite ordinal.[66] The Banach space

C(K)

is then isometric to . When

\alpha,\beta

are two countably infinite ordinals, and assuming

\alpha\leq\beta,

the spaces and are isomorphic if and only if .[67] For example, the Banach spacesC(\langle 1, \omega\rangle), \ C(\langle 1, \omega^ \rangle), \ C(\langle 1, \omega^\rangle), \ C(\langle 1, \omega^ \rangle), \cdots, C(\langle 1, \omega^ \rangle), \cdotsare mutually non-isomorphic.

Examples

See main article: List of Banach spaces.

Derivatives

Several concepts of a derivative may be defined on a Banach space. See the articles on the Fréchet derivative and the Gateaux derivative for details. The Fréchet derivative allows for an extension of the concept of a total derivative to Banach spaces. The Gateaux derivative allows for an extension of a directional derivative to locally convex topological vector spaces. Fréchet differentiability is a stronger condition than Gateaux differentiability. The quasi-derivative is another generalization of directional derivative that implies a stronger condition than Gateaux differentiability, but a weaker condition than Fréchet differentiability.

Generalizations

Several important spaces in functional analysis, for instance the space of all infinitely often differentiable functions

\R\to\R,

or the space of all distributions on

\R,

are complete but are not normed vector spaces and hence not Banach spaces. In Fréchet spaces one still has a complete metric, while LF-spaces are complete uniform vector spaces arising as limits of Fréchet spaces.

Bibliography

Notes and References

  1. It is common to read instead of the more technically correct but (usually) pedantic especially if the norm is well known (for example, such as with

    Lp

    spaces
    ) or when there is no particular need to choose any one (equivalent) norm over any other (especially in the more abstract theory of topological vector spaces), in which case this norm (if needed) is often automatically assumed to be denoted by

    \|\|.

    However, in situations where emphasis is placed on the norm, it is common to see

    (X,\|\|)

    written instead of

    X.

    The technically correct definition of normed spaces as pairs

    (X,\|\|)

    may also become important in the context of category theory where the distinction between the categories of normed spaces, normable spaces, metric spaces, TVSs, topological spaces, etc. is usually important.
  2. This means that if the norm

    \|\|

    is replaced with a different norm

    \|\|\prime

    on

    X,

    then

    (X,\|\|)

    is the same normed space as

    \left(X,\|\|\prime\right),

    not even if the norms are equivalent. However, equivalence of norms on a given vector space does form an equivalence relation.
  3. A metric

    D

    on a vector space

    X

    is said to be translation invariant if

    D(x,y)=D(x+z,y+z)

    for all vectors

    x,y,z\inX.

    This happens if and only if

    D(x,y)=D(x-y,0)

    for all vectors

    x,y\inX.

    A metric that is induced by a norm is always translation invariant.
  4. Because

    \|-z\|=\|z\|

    for all

    z\inX,

    it is always true that

    d(x,y):=\|y-x\|=\|x-y\|

    for all

    x,y\inX.

    So the order of

    x

    and

    y

    in this definition does not matter.
  5. see Theorem 1.3.9, p. 20 in .
  6. Let

    H

    be the separable Hilbert space

    \ell2(\N)

    of square-summable sequences with the usual norm

    \|\|2

    and let

    en=(0,\ldots,0,1,0,\ldots)

    be the standard orthonormal basis (that is

    1

    at the

    nth

    -coordinate). The closed set

    S=\{0\}\cup\left\{\tfrac{1}{n}en:n=1,2,\ldots\right\}

    is compact (because it is sequentially compact) but its convex hull

    \operatorname{co}S

    is a closed set because

    h:=

    infty
    \sum
    n=1

    \tfrac{1}{2n}\tfrac{1}{n}en

    belongs to the closure of

    \operatorname{co}S

    in

    H

    but

    h\not\in\operatorname{co}S

    (since every sequence

    \left(zn\right)

    infty
    n=1

    \in\operatorname{co}S

    is a finite convex combination of elements of

    S

    and so

    zn=0

    for all but finitely many coordinates, which is not true of

    h

    ). However, like in all complete Hausdorff locally convex spaces, the convex hull

    K:=\overline{\operatorname{co}}S

    of this compact subset is compact. The vector subspace

    X:=\operatorname{span}S=\operatorname{span}\left\{e1,e2,\ldots\right\}

    is a pre-Hilbert space when endowed with the substructure that the Hilbert space

    H

    induces on it but

    X

    is not complete and

    h\not\inC:=K\capX

    (since

    h\not\inX

    ). The closed convex hull of

    S

    in

    X

    (here, "closed" means with respect to

    X,

    and not to

    H

    as before) is equal to

    K\capX,

    which is not compact (because it is not a complete subset). This shows that in a Hausdorff locally convex space that is not complete, the closed convex hull of compact subset might to be compact (although it will be precompact/totally bounded).
  7. Web site: Equivalence of norms. https://ghostarchive.org/archive/20221009/https://kconrad.math.uconn.edu/blurbs/gradnumthy/equivnorms.pdf . 2022-10-09 . live. Conrad. Keith. kconrad.math.uconn.edu. September 7, 2020.
  8. Let

    \left(C([0,1]),\|\|infty\right)

    denote the Banach space of continuous functions with the supremum norm and let

    \tauinfty

    denote the topology on

    C([0,1])

    induced by

    \|\|infty.

    The vector space

    C([0,1])

    can be identified (via the inclusion map) as a proper dense vector subspace

    X

    of the

    L1

    space

    \left(L1([0,1]),\|\|1\right),

    which satisfies

    \|f\|1\leq\|f\|infty

    for all

    f\inX.

    Let

    p

    denote the restriction of the L1-norm to

    X,

    which makes this map

    p:X\to\R

    a norm on

    X

    (in general, the restriction of any norm to any vector subspace will necessarily again be a norm). The normed space

    (X,p)

    is a Banach space since its completion is the proper superset

    \left(L1([0,1]),\|\|1\right).

    Because

    p\leq\|\|infty

    holds on

    X,

    the map

    p:\left(X,\tauinfty\right)\to\R

    is continuous. Despite this, the norm

    p

    is equivalent to the norm

    \|\|infty

    (because

    \left(X,\|\|infty\right)

    is complete but

    (X,p)

    is not).
  9. see Corollary 1.4.18, p. 32 in .
  10. The normed space

    (\R,||)

    is a Banach space where the absolute value is a norm on the real line

    \R

    that induces the usual Euclidean topology on

    \R.

    Define a metric

    D:\R x \R\to\R

    on

    \R

    by

    D(x,y)=|\arctan(x)-\arctan(y)|

    for all

    x,y\in\R.

    Just like induced metric, the metric

    D

    also induces the usual Euclidean topology on

    \R.

    However,

    D

    is not a complete metric because the sequence

    x\bull=\left(xi\right)

    infty
    i=1
    defined by

    xi:=i

    is a sequence but it does not converge to any point of

    \R.

    As a consequence of not converging, this sequence cannot be a Cauchy sequence in

    (\R,||)

    (that is, it is not a Cauchy sequence with respect to the norm

    ||

    ) because if it was then the fact that

    (\R,||)

    is a Banach space would imply that it converges (a contradiction).
  11. Klee. V. L.. Invariant metrics in groups (solution of a problem of Banach). 1952. Proc. Amer. Math. Soc.. 3. 3. 484–487. https://ghostarchive.org/archive/20221009/https://www.ams.org/journals/proc/1952-003-03/S0002-9939-1952-0047250-4/S0002-9939-1952-0047250-4.pdf . 2022-10-09 . live. 10.1090/s0002-9939-1952-0047250-4. free.
  12. The statement of the theorem is: Let

    d

    be metric on a vector space

    X

    such that the topology

    \tau

    induced by

    d

    on

    X

    makes

    (X,\tau)

    into a topological vector space. If

    (X,d)

    is a complete metric space then

    (X,\tau)

    is a complete topological vector space.
  13. This metric

    D

    is assumed to be translation-invariant. So in particular, this metric

    D

    does even have to be induced by a norm.
  14. A norm (or seminorm)

    p

    on a topological vector space

    (X,\tau)

    is continuous if and only if the topology

    \taup

    that

    p

    induces on

    X

    is coarser than

    \tau

    (meaning,

    \taup\subseteq\tau

    ), which happens if and only if there exists some open ball

    B

    in

    (X,p)

    (such as maybe

    \{x\inX:p(x)<1\}

    for example) that is open in

    (X,\tau).

  15. X\prime

    denotes the continuous dual space of

    X.

    When

    X\prime

    is endowed with the strong dual space topology, also called the topology of uniform convergence on bounded subsets of

    X,

    then this is indicated by writing
    \prime
    X
    b
    (sometimes, the subscript

    \beta

    is used instead of

    b

    ). When

    X

    is a normed space with norm

    \|\|

    then this topology is equal to the topology on

    X\prime

    induced by the dual norm. In this way, the strong topology is a generalization of the usual dual norm-induced topology on

    X\prime.

  16. Gabriyelyan, S.S. "On topological spaces and topological groups with certain local countable networks (2014)
  17. Web site: Annoying Precision. Banach spaces (and Lawvere metrics, and closed categories). June 23, 2012. Qiaochu Yuan.
  18. The fact that

    \{x\inX:|f(x)|<1\}

    being open implies that

    f:X\to\R

    is continuous simplifies proving continuity because this means that it suffices to show that

    \{x\inX:\left|f(x)-f\left(x0\right)\right|<r\}

    is open for

    r:=1

    and at

    x0:=0

    (where

    f(0)=0

    ) rather than showing this for real

    r>0

    and

    x0\inX.

  19. see pp. 17–19 in .
  20. see, pp. 11-12.
  21. see, Th. 9 p. 185.
  22. see Theorem 6.1, p. 55 in
  23. Several books about functional analysis use the notation

    X*

    for the continuous dual, for example,,,, .
  24. Theorem 1.9.6, p. 75 in
  25. see also Theorem 2.2.26, p. 179 in
  26. see p. 19 in .
  27. Theorems 1.10.16, 1.10.17 pp.94–95 in
  28. Theorem 2.5.16, p. 216 in .
  29. see II.A.8, p. 29 in
  30. see Theorem 2.6.23, p. 231 in .
  31. see N. Bourbaki, (2004), "Integration I", Springer Verlag, .
  32. Dan . Amir . On isomorphisms of continuous function spaces . . 3 . 1965 . 4 . 205–210 . 10.1007/bf03008398 . free . 122294213 .
  33. M. . Cambern . A generalized Banach–Stone theorem . Proc. Amer. Math. Soc. . 17 . 1966 . 2 . 396–400 . 10.1090/s0002-9939-1966-0196471-9. free. And M. . Cambern . On isomorphisms with small bound . Proc. Amer. Math. Soc. . 18 . 1967 . 6 . 1062–1066 . 10.1090/s0002-9939-1967-0217580-2. free.
  34. H. B. . Cohen . A bound-two isomorphism between

    C(X)

    Banach spaces . Proc. Amer. Math. Soc. . 50 . 1975 . 215–217 . 10.1090/s0002-9939-1975-0380379-5. free .
  35. See for example Book: Arveson, W. . 1976 . An Invitation to C*-Algebra . Springer-Verlag . 0-387-90176-0 .
  36. R. C. James. A non-reflexive Banach space isometric with its second conjugate space. Proc. Natl. Acad. Sci. U.S.A.. 37. 174–177. 1951. 3 . 10.1073/pnas.37.3.174 . 1063327. 16588998. 1951PNAS...37..174J . free.
  37. see, p. 25.
  38. bishop. See E.. Phelps. R.. 1961. A proof that every Banach space is subreflexive. Bull. Amer. Math. Soc.. 67. 97–98. 10.1090/s0002-9904-1961-10514-4. free .
  39. see Corollary 2, p. 11 in .
  40. see p. 85 in .
  41. Rosenthal. Haskell P. 1974. A characterization of Banach spaces containing ℓ1. Proc. Natl. Acad. Sci. U.S.A.. 71. 6. 2411–2413 . 10.1073/pnas.71.6.2411. 16592162. 388466. math.FA/9210205. 1974PNAS...71.2411R. free. Rosenthal's proof is for real scalars. The complex version of the result is due to L. Dor, in Dor. Leonard E. 1975. On sequences spanning a complex ℓ1 space. Proc. Amer. Math. Soc. . 47. 515–516. 10.1090/s0002-9939-1975-0358308-x. free.
  42. Odell and Rosenthal, Sublemma p. 378 and Remark p. 379.
  43. for more on pointwise compact subsets of the Baire class, see .
  44. see Proposition 2.5.14, p. 215 in .
  45. see Corollary 2.8.9, p. 251 in .
  46. see p. 3.
  47. the question appears p. 238, §3 in Banach's book, .
  48. see S. V. Bočkarev, "Existence of a basis in the space of functions analytic in the disc, and some properties of Franklin's system". (Russian) Mat. Sb. (N.S.) 95(137) (1974), 3–18, 159.
  49. see Enflo. P.. 1973. A counterexample to the approximation property in Banach spaces. Acta Math.. 130. 309–317. 10.1007/bf02392270. 120530273 . free.
  50. see R.C. James, "Bases and reflexivity of Banach spaces". Ann. of Math. (2) 52, (1950). 518–527. See also p. 9.
  51. see A. Grothendieck, "Produits tensoriels topologiques et espaces nucléaires". Mem. Amer. Math. Soc. 1955 (1955), no. 16, 140 pp., and A. Grothendieck, "Résumé de la théorie métrique des produits tensoriels topologiques". Bol. Soc. Mat. São Paulo 8 1953 1–79.
  52. see chap. 2, p. 15 in .
  53. see chap. 3, p. 45 in .
  54. see Example. 2.19, p. 29, and pp. 49–50 in .
  55. see Proposition 4.6, p. 74 in .
  56. see Pisier, Gilles (1983), "Counterexamples to a conjecture of Grothendieck", Acta Math. 151:181–208.
  57. see Szankowski, Andrzej (1981), "

    B(H)

    does not have the approximation property", Acta Math. 147: 89–108. Ryan claims that this result is due to Per Enflo, p. 74 in .
  58. see Kwapień, S. (1970), "A linear topological characterization of inner-product spaces", Studia Math. 38:277–278.
  59. Lindenstrauss. Joram. Tzafriri. Lior. 1971. On the complemented subspaces problem. Israel Journal of Mathematics. 9. 2. 263–269. 10.1007/BF02771592 . free.
  60. see p. 245 in . The homogeneity property is called "propriété (15)" there. Banach writes: "on ne connaît aucun exemple d'espace à une infinité de dimensions qui, sans être isomorphe avec

    (L2).

    possède la propriété (15)".
  61. see Gowers. W. T.. 1994. A solution to Banach's hyperplane problem. Bull. London Math. Soc.. 26. 6. 523–530. 10.1112/blms/26.6.523.
  62. see Komorowski. Ryszard A.. Tomczak-Jaegermann. Nicole. 1995. Banach spaces without local unconditional structure. Israel Journal of Mathematics. 89. 1–3. 205–226. math/9306211. 10.1007/bf02808201. free. 5220304. and also Komorowski. Ryszard A.. Tomczak-Jaegermann. Nicole. 1998. Erratum to: Banach spaces without local unconditional structure. Israel Journal of Mathematics. 105. 85–92. math/9607205. 10.1007/bf02780323. free. 18565676.
  63. Book: C. Bessaga, A. Pełczyński. Selected Topics in Infinite-Dimensional Topology. 1975. Panstwowe wyd. naukowe. 177–230.
  64. Book: H. Torunczyk . Characterizing Hilbert Space Topology . Fundamenta Mathematicae . 1981 . 247–262.
  65. Milyutin, Alekseĭ A. (1966), "Isomorphism of the spaces of continuous functions over compact sets of the cardinality of the continuum". (Russian) Teor. Funkciĭ Funkcional. Anal. i Priložen. Vyp. 2:150–156.
  66. One can take, where

    \beta+1

    is the Cantor–Bendixson rank of

    K,

    and

    n>0

    is the finite number of points in the

    \beta

    -th derived set

    K(\beta)

    of

    K.

    See Mazurkiewicz, Stefan; Sierpiński, Wacław (1920), "Contribution à la topologie des ensembles dénombrables", Fundamenta Mathematicae 1: 17–27.
  67. Bessaga, Czesław; Pełczyński, Aleksander (1960), "Spaces of continuous functions. IV. On isomorphical classification of spaces of continuous functions", Studia Math. 19:53–62.