Austin moving-knife procedures explained

The Austin moving-knife procedures are procedures for equitable division of a cake. To each of n partners, they allocate a piece of the cake which this partner values as exactly

1/n

of the cake. This is in contrast to proportional division procedures, which give each partner at least

1/n

of the cake, but may give more to some of the partners.

When

n=2

, the division generated by Austin's procedure is an exact division and it is also envy-free. Moreover, it is possible to divide the cake to any number k of pieces which both partners value as exactly 1/k. Hence, it is possible to divide the cake between the partners in any fraction (e.g. give 1/3 to Alice and 2/3 to George).

When

n>2

, the division is neither exact nor envy-free, since each partner only values his own piece as

1/n

, but may value other pieces differently.

The main mathematical tool used by Austin's procedure is the intermediate value theorem (IVT).[1] [2]

Two partners and half-cakes

The basic procedures involve

n=2

partners who want to divide a cake such that each of them gets exactly one half.

Two knives procedure

For the sake of description, call the two players Alice and George, and assume the cake is rectangular.

One knife procedure

A single knife can be used to achieve the same effect.

Alice must of course end the turn with the knife on the same line as where it started. Again, by the IVT, there must be a point in which George feels that the two halves are equal.

Two partners and general fractions

As noted by Austin, the two partners can find a single piece of cake that both of them value as exactly

1/k

, for any integer

k\geq2

. Call the above procedure

Cut2(1/k)

:

k-1

parallel marks on the cake such that

k

pieces so determined have a value of exactly

1/k

.

1/k

, then we are done.

1/k

, and an adjacent piece that George values as more than

1/k

.

1/k

, until they meet the marks of the other piece. By the IVT, there must be a point at which George agrees that the value between the knives is exactly

1/k

.

By recursively applying

Cut2

, the two partners can divide the entire cake to

k

pieces, each of which is worth exactly

1/k

for both of them:

Cut2(1/k)

to cut a piece which is worth exactly

1/k

for both partners.

(k-1)/k

for both partners; use

Cut2(1/(k-1))

to cut another piece worth exactly

1/k

for both partners.

k

pieces.

Two partners can achieve an exact division with any rational ratio of entitlements by a slightly more complicated procedure.

Many partners

By combining

Cut2

with the Fink protocol, it is possible to divide a cake to

n

partners, such that each partner receives a piece worth exactly

1/n

for him:[3]

Cut2(1/2)

to give each one of them a piece worth exactly 1/2 for them.

Cut2(1/3)

with partner #1 to get exactly 1/3 of his share and then

Cut2(1/3)

with partner #2 to get exactly 1/3 of her share. The first piece is worth exactly 1/6 for partner #1 and so partner #1 remains with exactly 1/3; the same is true for partner #2. As for partner #3, while each piece can be more or less than 1/6, the sum of the two pieces must be exactly 1/3 of the entire cake.

Note that for

n>2

, the generated division is not exact, since a piece is worth

1/n

only to its owner and not necessarily to the other partners. As of 2015, there is no known exact division procedure for

n>2

partners; only near-exact division procedures are known.

See also

External links

Notes and References

  1. 10.2307/3616548. 3616548. Sharing a Cake. The Mathematical Gazette. 66. 437. 212–215. 1982. Austin . A. K.. 158398839.
  2. Book: 978-0-521-55644-6 . Fair Division . From cake-cutting to dispute resolution . Brams . Steven J. . 1996. Taylor . Alan D. . 22–27 .
  3. Book: 978-0-521-55644-6 . Fair Division . From cake-cutting to dispute resolution . Brams . Steven J. . . Taylor . Alan D. . 43–44 .