Apollonius's theorem explained

In geometry, Apollonius's theorem is a theorem relating the length of a median of a triangle to the lengths of its sides. It states that the sum of the squares of any two sides of any triangle equals twice the square on half the third side, together with twice the square on the median bisecting the third side. The theorem is named for the ancient Greek mathematician Apollonius of Perga.

Statement and relation to other theorem

In any triangle

ABC,

if

AD

is a median, then |AB|^2+|AC|^2=2(|BD|^2+|AD|^2).It is a special case of Stewart's theorem. For an isosceles triangle with

|AB|=|AC|,

the median

AD

is perpendicular to

BC

and the theorem reduces to the Pythagorean theorem for triangle

ADB

(or triangle

ADC

). From the fact that the diagonals of a parallelogram bisect each other, the theorem is equivalent to the parallelogram law.

Proof

The theorem can be proved as a special case of Stewart's theorem, or can be proved using vectors (see parallelogram law). The following is an independent proof using the law of cosines.[1]

Let the triangle have sides

a,b,c

with a median

d

drawn to side

a.

Let

m

be the length of the segments of

a

formed by the median, so

m

is half of

a.

Let the angles formed between

a

and

d

be

\theta

and

\theta\prime,

where

\theta

includes

b

and

\theta\prime

includes

c.

Then

\theta\prime

is the supplement of

\theta

and

\cos\theta\prime=-\cos\theta.

The law of cosines for

\theta

and

\theta\prime

states that\beginb^2 &= m^2 + d^2 - 2dm\cos\theta \\c^2 &= m^2 + d^2 - 2dm\cos\theta' \\&= m^2 + d^2 + 2dm\cos\theta.\, \end

Add the first and third equations to obtainb^2 + c^2 = 2(m^2 + d^2)as required.

External links

Notes and References

  1. Book: Modern Geometry. Charles. Godfrey. Arthur Warry. Siddons. University Press. 1908. 20.