Alexandroff plank explained

Alexandroff plank in topology, an area of mathematics, is a topological space that serves as an instructive example.

Definition

The construction of the Alexandroff plank starts by defining the topological space

(X,\tau)

to be the Cartesian product of

[0,\omega1]

and

[-1,1],

where

\omega1

is the first uncountable ordinal, and both carry the interval topology. The topology

\tau

is extended to a topology

\sigma

by adding the sets of the formU(\alpha,n) = \ \cup (\alpha,\omega_1] \times (0,1/n)where

p=(\omega1,0)\inX.

The Alexandroff plank is the topological space

(X,\sigma).

It is called plank for being constructed from a subspace of the product of two spaces.

Properties

The space

(X,\sigma)

has the following properties:
  1. It is Urysohn, since

(X,\tau)

is regular. The space

(X,\sigma)

is not regular, since

C=\{(\alpha,0):\alpha<\omega1\}

is a closed set not containing

(\omega1,0),

while every neighbourhood of

C

intersects every neighbourhood of

(\omega1,0).

  1. It is semiregular, since each basis rectangle in the topology

\tau

is a regular open set and so are the sets

U(\alpha,n)

defined above with which the topology was expanded.
  1. It is not countably compact, since the set

\{(\omega1,-1/n):n=2,3,...\}

has no upper limit point.
  1. It is not metacompact, since if

\{V\alpha\}

is a covering of the ordinal space

[0,\omega1)

with not point-finite refinement, then the covering

\{U\alpha\}

of

X

defined by

U1=\{(0,\omega1)\}\cup([0,\omega1] x (0,1]),

U2=[0,\omega1] x [-1,0),

and

U\alpha=V\alpha x [-1,1]

has not point-finite refinement.

References