Abel's summation formula explained

In mathematics, Abel's summation formula, introduced by Niels Henrik Abel, is intensively used in analytic number theory and the study of special functions to compute series.

Formula

Let

(an)

infty
n=0
be a sequence of real or complex numbers. Define the partial sum function

A

by

A(t)=\sum0an

for any real number

t

. Fix real numbers

x<y

, and let

\phi

be a continuously differentiable function on

[x,y]

. Then:

\sumxan\phi(n)=A(y)\phi(y)-A(x)\phi(x)-

y
\int
x

A(u)\phi'(u)du.

The formula is derived by applying integration by parts for a Riemann–Stieltjes integral to the functions

A

and

\phi

.

Variations

Taking the left endpoint to be

-1

gives the formula

\sum0an\phi(n)=A(x)\phi(x)-

x
\int
0

A(u)\phi'(u)du.

If the sequence

(an)

is indexed starting at

n=1

, then we may formally define

a0=0

. The previous formula becomes

\sum1an\phi(n)=A(x)\phi(x)-

x
\int
1

A(u)\phi'(u)du.

A common way to apply Abel's summation formula is to take the limit of one of these formulas as

x\toinfty

. The resulting formulas are
infty
\begin{align} \sum
n=0

an\phi(n)&=\limxl(A(x)\phi(x)r)-

infty
\int
0

A(u)\phi'(u)du,

infty
\\ \sum
n=1

an\phi(n)&=\limxl(A(x)\phi(x)r)-

infty
\int
1

A(u)\phi'(u)du. \end{align}

These equations hold whenever both limits on the right-hand side exist and are finite.

A particularly useful case is the sequence

an=1

for all

n\ge0

. In this case,

A(x)=\lfloorx+1\rfloor

. For this sequence, Abel's summation formula simplifies to

\sum0\phi(n)=\lfloorx+1\rfloor\phi(x)-

x
\int
0

\lflooru+1\rfloor\phi'(u)du.

Similarly, for the sequence

a0=0

and

an=1

for all

n\ge1

, the formula becomes

\sum1\phi(n)=\lfloorx\rfloor\phi(x)-

x
\int
1

\lflooru\rfloor\phi'(u)du.

Upon taking the limit as

x\toinfty

, we find
infty
\begin{align} \sum
n=0

\phi(n)&=\limxl(\lfloorx+1\rfloor\phi(x)r)-

infty
\int
0

\lflooru+1\rfloor\phi'(u)du,

infty
\\ \sum
n=1

\phi(n)&=\limxl(\lfloorx\rfloor\phi(x)r)-

infty
\int
1

\lflooru\rfloor\phi'(u)du, \end{align}

assuming that both terms on the right-hand side exist and are finite.

Abel's summation formula can be generalized to the case where

\phi

is only assumed to be continuous if the integral is interpreted as a Riemann–Stieltjes integral:

\sumxan\phi(n)=A(y)\phi(y)-A(x)\phi(x)-

y
\int
x

A(u)d\phi(u).

By taking

\phi

to be the partial sum function associated to some sequence, this leads to the summation by parts formula.

Examples

Harmonic numbers

If

an=1

for

n\ge1

and

\phi(x)=1/x,

then

A(x)=\lfloorx\rfloor

and the formula yields
\lfloorx\rfloor
\sum
n=1
1
n

=

\lfloorx\rfloor
x

+

x
\int
1
\lflooru\rfloor
u2

du.

The left-hand side is the harmonic number

H\lfloor

.

Representation of Riemann's zeta function

Fix a complex number

s

. If

an=1

for

n\ge1

and

\phi(x)=x-s,

then

A(x)=\lfloorx\rfloor

and the formula becomes
\lfloorx\rfloor
\sum
n=1
1
ns

=

\lfloorx\rfloor
xs

+

x
s\int
1
\lflooru\rfloor
u1+s

du.

If

\Re(s)>1

, then the limit as

x\toinfty

exists and yields the formula

\zeta(s)=

infty
s\int
1
\lflooru\rfloor
u1+s

du.

where

\zeta(s)

is the Riemann zeta function.This may be used to derive Dirichlet's theorem that

\zeta(s)

has a simple pole with residue 1 at .

Reciprocal of Riemann zeta function

The technique of the previous example may also be applied to other Dirichlet series. If

an=\mu(n)

is the Möbius function and

\phi(x)=x-s

, then

A(x)=M(x)=\sumn\mu(n)

is Mertens function and
1
\zeta(s)

=

infty
\sum
n=1
\mu(n)
ns

=

infty
s\int
1
M(u)
u1+s

du.

This formula holds for

\Re(s)>1

.

See also

References