Tournament Name: | 2019 BetVictor Snooker Shoot Out |
Venue: | Watford Colosseum |
Location: | Watford |
Country: | England |
Organisation: | World Snooker |
Format: | Ranking event |
Total Prize Fund: | £146,000 |
Winners Share: | £32,000 |
Score: | 74–0 (one frame) |
Previous: | 2018 |
Next: | 2020 |
The 2019 Shoot Out (officially the 2019 BetVictor Snooker Shoot Out) was a professional ranking snooker tournament, taking place from 21 to 24 February 2019 at the Watford Colosseum in Watford, England.[1] [2] It was played under a variation of the standard rules of snooker, and it was the fourteenth ranking event of the 2018/2019 season.
Michael Georgiou was the defending champion, but he lost to Li Hang 28–45 in the second round.[3]
Thepchaiya Un-Nooh won his first career ranking title, beating Michael Holt 74–0 in the final. Un-Nooh's 139 break in the semi-final was the highest in the history of the Shoot Out.[4]
The tournament was played using a variation of the traditional snooker rules. The draw was randomised before each round. All matches were played over a single, each of which lasted up to 10 minutes. The event featured a variable ; shots played in the first five minutes were allowed 15 seconds while the final five had a 10-second timer. All awarded the opponent a . Unlike traditional snooker, if a ball did not hit a on every shot, it was a foul. Rather than a coin toss, a lag was used to choose which player . In the event of a draw, each player received a shot at the this is known as a "blue ball shootout". The player who the ball with the from inside the and the blue ball on its spot with the opponent missing won the match.
The breakdown of prize money for this year is shown below:[5]
All times in Greenwich Mean Time. Times for quarter-finals, semi-finals and final are approximate. Players in bold denote match winners.
Note: w/d=withdrawn; w/o=walk-over
Final: 1 frame. Referee: Brendan Moore Watford Colosseum, Watford, England, 24 February 2019 – 22:45 | |||
Thepchaiya Un-Nooh | 74–0 | Michael Holt |
Total: 4[6]