2019 BNP Paribas Open – Women's singles explained

Champ:	Bianca Andreescu
Runner:	Angelique Kerber
Score:	6–4, 3–6, 6–4
Draw:	96
Seeds:	32
Main Name:	Indian Wells Open
Before Name:	BNP Paribas Open – Women's singles
After Name:	BNP Paribas Open – Women's singles
After Year:	2021

See main article: 2019 BNP Paribas Open.

Bianca Andreescu defeated Angelique Kerber in the final, 6–4, 3–6, 6–4 to win the women's singles tennis title at the 2019 Indian Wells Open. It was her first WTA Tour title, and she became the first wildcard champion in tournament history, as well as the youngest champion since Serena Williams in 1999.^[1] This marked the second consecutive year where a player won the tournament as her first WTA singles title.

Naomi Osaka was the defending champion, but lost to Belinda Bencic in the fourth round.^[2] Osaka retained the WTA No. 1 singles ranking despite failing to defend her title. Petra Kvitová, Simona Halep, Sloane Stephens and Karolína Plíšková were also in contention for the top ranking.^[3]

Seeds

All seeds received a bye into the second round.

Draw

Top half

Section 4

Bottom half

Section 8

Qualifying

Draw

Twelfth qualifier

External links

• Main draw
• Qualifying draw

Notes and References

1. Web site: Andreescu surprises Svitolina to reach biggest final of her career at Indian Wells. WTA Tennis.
2. Web site: A toast to BNP Paribas Open singles champion Naomi Osaka — just don't make it sourdough toast. Desert Sun.
3. Web site: Indian Wells Draw Analysis: No.1 on the line as Osaka seeks rare title defense in the desert. WTA Tennis.