2014 U.S. Open 9-ball Championship explained

The 2014 US Open 9-Ball Championship was the 39th edition the U.S. Open 9-Ball Championships. The event took place between 12-18 October 2014 in Marriott Chesapeake in Chesapeake, Virginia, USA.

The winner of the tournament was Shane Van Boening winning 13-10 in the final against Dennis Orcollo.^[1] This was Van Boening's fourth title after having won the tournament in 2007, 2012 and 2013. This was also Van Boening's third championship in a row, which had never been done before.^[2] In total, the event had a total prize pool of $178,000, with the winner receiving 24,000 US dollars.

Tournament format

The tournament was played as a Double-elimination tournament. In the preliminary round was played until one of the two players 11 games (so-called. Racks) had won; in the final was played to 13. The event was played as winner breaks.

Ranking

The following were the 32 best placed players.^[3]

Place Player 1 Shane Van Boening 2 Dennis Orcollo 3 Nikos Ekonomopoulos 4 Mike Dechaine 5 Warren Kiamco Francisco Bustamante 7 Justin Hall Jason Klatt 9 Ernesto Domínguez Thorsten Hohmann Karl Boyes Darren Appleton 13 Efren Reyes Chris Futrell Daryl Peach Do Hoang Quan

Place Player 17 Kenichi Uchigaki John Morra Alexander Kazakis Justin Bergman Corey Deuel Waleed Majid Nick van den Berg Niels Feijen 25 Li Hewen Jeremy Sossei Jonathan Pinegar Earl Strickland Rodrigo Geronimo Liu Haitao Chris Bruner Raj Hundal

Notes and References

1. Web site: 6185 - US Open 9-Ball Championship 2014 . AzBilliards . 10 August 2023 .
2. Web site: Van Boening Wins Third Straight US Open Title . AzBilliards . 10 August 2023 .
3. Web site: 6185 - US Open 9-Ball Championship 2014 . AzBilliards . 10 August 2023 .