2006 United States Virgin Islands general election explained

Election Name:2006 United States Virgin Islands gubernatorial election
Country:United States Virgin Islands
Type:presidential
Ongoing:No
Previous Election:2002 United States Virgin Islands general election
Previous Year:2002
Next Election:2010 United States Virgin Islands gubernatorial election
Next Year:2010
Election Date:7 November 2006 (general)
21 November 2006 (run off)
Nominee1:John de Jongh
Running Mate1:Gregory Francis
Party1:Democratic Party (United States)
Popular Vote1:16,644
Percentage1:57.18%
Nominee2:Kenneth Mapp
Running Mate2:Almando "Rocky" Liburd
Party2:Independent (United States)
Popular Vote2:12,402
Percentage2:42.61
Governor
Before Election:Charles W. Turnbull
Before Party:Democratic Party (United States)
After Election:John de Jongh
After Party:Democratic Party (United States)

The 2006 U.S. Virgin Islands general election took place on 7 November 2006 in order to elect the Governor of the United States Virgin Islands, 15 members of the Legislature and the Delegate to United States House of Representatives. Incumbent Democratic Governor Charles Wesley Turnbull was term-limited and couldn't run for re-election to a third term in office. John de Jongh failed to win in the first round by just 2 votes,[1] since no candidate received a majority in the general election, as required by the Revised Organic Act of the Virgin Islands, a runoff was held between John de Jongh and Kenneth Mapp, the two top vote getters.[2]

Notes and References

  1. News: Susan . Mann . DeJongh wins USVI gubernatorial runoff election . Caribbean Net News . 22 November 2006 . https://web.archive.org/web/20100610011248/http://www.caribbeannetnews.com/cgi-script/csArticles/articles/000043/004388.htm . 10 June 2010.
  2. Web site: DeJongh Is Top Vote Getter in Governor's Race; Runoff With Mapp Likely . St. Thomas Source . November 7, 2006.