2005 US Open – Women's singles explained

See main article: 2005 US Open (tennis). Kim Clijsters defeated Mary Pierce in the final, 6–3, 6–1 to win the women's singles tennis title at the 2005 US Open. It was her first major singles title (following four runner-up finishes in major finals) and the first of an eventual three US Open titles.

Svetlana Kuznetsova was the defending champion, but was defeated by Ekaterina Bychkova in the first round. Kuznetsova became the first US Open champion to lose in the first round of her title defense.[1]

This was the first major tournament in which Maria Sharapova competed as the world No. 1.[2] She was defeated in the semifinals by Clijsters. This was also the final major appearance for former world No. 2 and 1994 Wimbledon champion Conchita Martínez.

Qualifying

See main article: article and 2005 US Open – Women's singles qualifying.

Draw

Top half

Section 4

Bottom half

Section 8

Championship match statistics

Category Clijsters Pierce
1st serve %33/47 (70%) 33/49 (67%)
1st serve points won27 of 33 = 82% 17 of 33 = 52%
2nd serve points won5 of 14 = 36% 6 of 16 = 38%
Total service points won32 of 47 = 68.09% 23 of 49 = 46.94%
Aces5 1
Double faults 2 1
Winners10 6
Unforced errors10 19
Net points won 4 of 4 = 100% 9 of 15 = 60%
Break points converted 5 of 11 = 45% 1 of 4 = 25%
Return points won 26 of 49 = 53% 15 of 47 = 32%
Total points won bgcolor=98FB98958 38
Source

External links

Notes and References

  1. News: Champion Kuznetsova crashes out. 2010-09-06. 2005-08-29. BBC News.
  2. http://www.abc.net.au/news/2005-08-22/sharapova-claims-world-number-one-ranking/2086824 Sharapova claims world number one ranking - ABC News (Australian Broadcasting Corporation)