2002 United States Virgin Islands general election explained

Election Name:2002 United States Virgin Islands gubernatorial election
Country:United States Virgin Islands
Type:presidential
Ongoing:No
Previous Election:1998 United States Virgin Islands general election
Previous Year:1998
Next Election:2006 United States Virgin Islands general election
Next Year:2006
Election Date:November 5, 2002
Image1:CharlesTurnbull (3x4 crop).jpg
Nominee1:Charles Turnbull
Running Mate1:Vargrave Richards
Party1:Democratic Party (United States)
Popular Vote1:17,545
Percentage1:50.25%
Nominee2:John de Jongh
Running Mate2:Paul Arnold Sr.
Party2:Independent (United States)
Popular Vote2:8,618
Percentage2:24.68%
Governor
Before Election:Charles Wesley Turnbull
Before Party:Democratic Party (United States)
After Election:Charles Wesley Turnbull
After Party:Democratic Party (United States)

The 2002 U.S. Virgin Islands gubernatorial election took place on 5 November 2002 in order to elect the Governor of the United States Virgin Islands, 15 members of the Legislature and the Delegate to United States House of Representatives. The election was held concurrently with the 2002 United States midterm elections.

Incumbent Democratic Governor Charles Wesley Turnbull won re-election with 50% of the vote over Independent candidate John de Jongh.[1]

Notes and References

  1. Web site: UNOFFICIAL RESULTS OF 2002 GENERAL ELECTIONS . St. Thomas Source. 6 November 2002 .