1994–95 Wills Triangular Series Explained
The 1994–95 Wills Triangular Series was a One Day International cricket tournament played entirely in Pakistan. It was held in October, with players from Australia, South Africa and Pakistan. Tournament started with the match between Australia and South Africa. In the final, Australia defeated Pakistan by 64 runs to win the tournament.
Using the round robin format, each team played the others three times, before top two teams reaching the final.
Group stage
Points table
Pos | Team | | | | | | | | |
---|
1 | | 6 | 4 | 1 | 0 | 1 | 0 | 9 | +4.773 |
2 | | 6 | 4 | 1 | 0 | 1 | 0 | 9 | +4.551 |
3 | | 6 | 0 | 6 | 0 | 0 | 0 | 0 | −4.110 | |
Fixtures
Final
Statistics
Batting
- Most runs[1]
Bowling
- Most wickets[2]
External links
- http://www.espncricinfo.com/ci/content/series/60960.html
Notes and References
- Web site: Wills Triangular Series, 1994-95 – Most runs . Cricinfo.com . ESPN . 25 October 2015 .
- Web site: Wills Triangular Series, 1994-95 – Most wickets . Cricinfo.com . ESPN . 25 October 2015 .