1993 Wimbledon Championships – Boys' singles explained

Champ: Răzvan Sabău
Runner: Jimy Szymanski
Score:6–1, 6–3
Before Name:Wimbledon Championships – Boys' singles
After Name:Wimbledon Championships – Boys' singles

See main article: 1993 Wimbledon Championships. Răzvan Sabău defeated Jimy Szymanski in the final, 6–1, 6–3 to win the boys' singles tennis title at the 1993 Wimbledon Championships.[1]

Seeds

See also: 1 and 1. Neville Godwin (second round)

See also: 2 and 4. Paul Goldstein (first round)

See also: 3 and 2. Lars Burgsmüller (quarterfinals)

See also: 4 and 3. Lars Rehmann (third round)

See also: 5 and 3. Filip Kaščák (first round)

See also: 6 and 2. Nicolas Escudé (semifinals)

See also: 7 and 1. Jimy Szymanski (final)

See also: 8 and 4. Steven Downs (second round)

See also: 9 and 4. Răzvan Sabău (champion)

See also: 10 and 1. James Sekulov (second round)

See also: 11 and 2. Gustavo Kuerten (third round)

See also: 12 and 3. Sebastián Prieto (first round)

See also: 13 and 3. Dennis van Scheppingen (second round)

See also: 14 and 2. Franco Squillari (first round)

See also: 15 and 4. James Baily (second round)

See also: 16 and 1. Jason Appel (quarterfinals)

Draw

Top half

Section 2

Bottom half

Section 4

External links

Notes and References

  1. Web site: Boys' Singles Finals 1947-2017. wimbledon.com. Wimbledon Championships. 13 August 2017.