1991 Tour of Britain explained
The 1991 Tour of Britain was the fifth edition of the Kellogg's Tour of Britain cycle race and was held from 6 August to 10 August 1991. The race started in Windsor and finished in Leeds.[1] The race was won by Phil Anderson of the Motorola team.
Route
Stage characteristics and winnersStage | Date | Course | Distance | Type | Winner |
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1 | 6 August | Windsor to Birmingham | 212.9km (132.3miles) | | | |
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2 | 7 August | Coventry to Lincoln | 191.3km (118.9miles) | | | |
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3 | 8 August | Lincoln to Buxton | 183km (114miles) | | | |
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4a | 9 August | Buxton to Manchester | 108km (67miles) | | | |
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4b | Manchester to Liverpool | 91.2km (56.7miles) | | | |
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5 | 10 August | Liverpool to Leeds | 208km (129miles) | | Hilly stage | | |
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General classification
Final general classification[2] Rank | Rider | Team | Time |
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1 | | | | 2 | | | + 1" | 3 | | | + 1" | 4 | | | + 17" | 5 | | | + 41" | 6 | | | + 53" | 7 | | | + 53" | 8 | | Banana–Falcon | + 53" | 9 | | | + 56" | 10 | | | + 3' 20" | |
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Notes and References
- Web site: Tour de Grande-Bretagne 1991. Memoire du cyclisme. https://web.archive.org/web/20040828180856/http://www.memoire-du-cyclisme.net/anc_grbretagne/td_grbretagne1991.php. 28 August 2004.
- News: Anderson gana en Inglaterra. Spanish. Anderson wins in England. El Mundo Deportivo. 35. 11 August 1991. 24 December 2017.