1990 Maryland gubernatorial election explained

Election Name:1990 Maryland gubernatorial election
Country:Maryland
Type:Presidential
Ongoing:no
Turnout:54.85%[1]
Previous Election:1986 Maryland gubernatorial election
Previous Year:1986
Next Election:1994 Maryland gubernatorial election
Next Year:1994
Election Date:November 6, 1990
Image1:File:William Donald Schaefer.jpg
Nominee1:William Donald Schaefer
Party1:Democratic Party (United States)
Running Mate1:Melvin Steinberg
Popular Vote1:664,015
Percentage1:59.76%
Nominee2:William S. Shepard
Party2:Republican Party (United States)
Running Mate2:Lois Shepard
Popular Vote2:446,980
Percentage2:40.23%
Map Size:295px
Governor
Before Election:William Donald Schaefer
Before Party:Democratic Party (United States)
After Election:William Donald Schaefer
After Party:Democratic Party (United States)

The 1990 Maryland gubernatorial election was held on November 6, 1990. Incumbent Democrat William Donald Schaefer defeated Republican nominee William S. Shepard handily (59.76% to 40.23%).

, this was the last occasion that the following counties have voted Democratic in a gubernatorial election: Cecil, Calvert, Harford, St. Mary's, and Worcester.

Primary elections

Primary elections were held on September 11, 1990.[2]

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Results

Notes and References

  1. Web site: 1990 Gubernatorial Election . elections.maryland.gov . . May 1, 2022.
  2. Web site: 1990 Gubernatorial Primary Election Results . Elections.maryland.gov . 2018-11-11.