1990 CONCACAF Champions' Cup explained

Year:1990
Dates:12 November 1990 (to)
12 March 1991
Num Teams:3
Associations:3
Champion Other: América
Count:3
Second Other: Pinar del Río
Matches:52
Goals:116
Prevseason:1989
Nextseason:1991

The 1990 CONCACAF Champions' Cup was the 26th edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's club champion of association football in the CONCACAF region and was played from 31 March 1990 till 12 March 1991.

The teams were split in three zones (North, Central and Caribbean), each one qualifying the winner to the final tournament, where the winners of the North and Central zones played a semi-final to decide who was going to play against the Caribbean champion in the final.

Mexican club América easily defeat Cuban side Pinar del Río 7–1 on aggregate,[1] winning their third CONCACAF trophy.[2]

North American Zone

First round

Second round

Central American Zone

First round

Torneo Centroamericano de Concacaf 1990|}

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Second round

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Third round

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Caribbean Zone

Preliminary round

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First round

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Second round

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Pinar del Río - (qualified)
Transvaal - (Eliminated)
Excelsior - (Eliminated)

Semi-finals

1st leg: Nov. 12, 1990 at San Jose, California – (USA)
2nd leg: Nov. 14, 1990 at Santa Ana, California(USA)|}

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Final

First

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Second leg

América won 3–1 on points (8–2 on aggregate).

Notes and References

  1. https://www.rsssf.org/tablesc/cacups90.html Copa de Campeones 1990
  2. http://www.realidadamericanista.com/palmares/titulos/371-america-campeon-de-concacaf-91-91-vs-pinar-del-rio.html Campeón de Concacaf 90–91