1988 Arab Cup final explained

1988 Arab Cup Final
Event:1988 Arab Cup
Team1:Iraq
Team1association:
Team1score:1
Team2:Syria
Team2association:
Team2score:1
Details:Iraq won 4–3 on penalties
Date:21 July 1988
Stadium:Amman International Stadium
City:Amman
Referee:Abdelali Naciri (Morocco)
Attendance:15 000
Previous:1985
Next:1992

The 1988 Arab Cup Final was a football match that took place on 21 July 1988, at the Amman International Stadium in Amman, Jordan, to determine the winner of the 1988 Arab Cup. Iraq defeated Syria 4–3 on penalties after a draw 1–1 to win their fourth Arab Cup.[1]

Road to the final

IraqSyria
OpponentsResultsOpponentsResults
Group stage
1–11–1
0–02–1
2–01–0
0–00–2
Semi-finals
3–00–0

Match

Details

Iraq:
width=25!width=25
GK 1 Ahmad Jassim
DF 3Hassan Kamal
DF 4
DF 5 Samir Shaker (c)
DF 13Karim Allawi
MF 6 Habib Jafar
MF 9Ismail Mohammed
MF 14 Basil Gorgis
FW 8Ahmed Radhi
FW 11Saad Qais
FW 15 Younis Abed Ali
Substitutes:
GK 22Omar Ahmed Tawfiq
DF 12Mudhafar Jabbar
DF 18Karim Salman
MF 2Salam Hashim
MF 7Naeem Saddam
MF 10Rahim Hameed
MF 17
Manager:
Ammo Baba
Syria:
width=25!width=25
GK 22Malek Shakuhi
DF 3Ammar Habib
DF 4Yousef Hawla
DF 12 Ahmad Al-Shaar
DF 17Samer Darwish
MF 6Saad Saad
MF 8Abdul Kader Kardaghli (c)
MF 14 Mohammad Jakalan
FW 9Nizar Mahrous
FW 11Hussein Deeb
FW 18Walid Al-Nasser
Substitutes:
GK 21 Walid Islam
DF 13 Abdullah Saddikah
DF 19
MF 10
MF 25 Radwan Ajam
Manager:
Anatoliy Azarenkov
Assistant referees


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Fourth official


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Man of the Match:
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External links

Notes and References

  1. Web site: كأس العرب الخامسة في السعودية 1988 النهائي . kooora.com .