1988 Arab Cup final explained
The 1988 Arab Cup Final was a football match that took place on 21 July 1988, at the Amman International Stadium in Amman, Jordan, to determine the winner of the 1988 Arab Cup. Iraq defeated Syria 4–3 on penalties after a draw 1–1 to win their fourth Arab Cup.[1]
Road to the final
Iraq | Syria |
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Opponents | Results | Opponents | Results |
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Group stage |
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| 1–1 | | 1–1 |
| 0–0 | | 2–1 |
| 2–0 | | 1–0 |
| 0–0 | | 0–2 |
Semi-finals |
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| 3–0 | | 0–0 | |
Match
Details
Assistant referees ... ... (...) ... ... (...) Fourth official
... ... (...)
| Man of the Match: ... ... (...) | |
External links
Notes and References
- Web site: كأس العرب الخامسة في السعودية 1988 النهائي . kooora.com .