1986 Wimbledon Championships – Girls' singles explained

Champ: Natasha Zvereva
Runner: Leila Meskhi
Score:2–6, 6–2, 9–7
Before Name:Wimbledon Championships – Girls' singles
After Name:Wimbledon Championships – Girls' singles

See main article: 1986 Wimbledon Championships. Natasha Zvereva defeated Leila Meskhi in the final, 2–6, 6–2, 9–7 to win the girls' singles tennis title at the 1986 Wimbledon Championships.[1]

Seeds

See also: 1 and 1. Claudia Porwik (first round)

See also: 2 and 4. Patricia Tarabini (second round)

See also: 3 and 2. Nicole Provis (second round)

See also: 4 and 3. Wiltrud Probst (quarterfinals)

See also: 5 and 3. Michelle Jaggard (semifinals)

See also: 6 and 1. Dinky van Rensburg (third round)

See also: 7 and 2. Hellas ter Riet (third round)

See also: 8 and 3. Jana Novotná (third round)

See also: 9 and 4. Emmanuelle Derly (second round)

See also: 10 and 3. Cécile Calmette (second round)

See also: 11 and 1. Bettina Fulco (third round)

See also: 12 and 1. Gisele Miró (semifinals)

See also: 13 and 4. Gisele Faria (second round)

See also: 14 and 2. Ann Devries (quarterfinals)

See also: 15 and 3. Rona Daniels (first round)

See also: 16 and 2. Gabriela Mosca (second round)

Draw

Top half

Section 2

Bottom half

Section 4

External links

Notes and References

  1. Web site: Girls' Singles Finals 1947-2017. wimbledon.com. Wimbledon Championships. 13 August 2017.