1986 Wimbledon Championships – Girls' doubles explained

Champ: Michelle Jaggard
Lisa O'Neill
Runner: Leila Meskhi
Natasha Zvereva
Score:7–6(7–3), 6–7(4–7), 6–4
Before Name:Wimbledon Championships – Girls' doubles
After Name:Wimbledon Championships – Girls' doubles

See main article: 1986 Wimbledon Championships. Michelle Jaggard and Lisa O'Neill defeated Leila Meskhi and Natasha Zvereva in the final, 7–6(7–3), 6–7(4–7), 6–4 to win the girls' doubles tennis title at the 1986 Wimbledon Championships.[1]

Seeds

The top 3 seeds received a bye into the second round.

  1. Alexia Dechaume / Sybille Niox-Château (quarterfinals)
  2. Gisele Miró / Patricia Tarabini (quarterfinals)
  3. Kim Il-soon / Jennifer Saberon (semifinals)
  4. Gisele Faria / Frédérique Martin (quarterfinals)
  5. Wiltrud Probst / Eva-Maria Schürhoff (semifinals)
  6. Leila Meskhi / Natasha Zvereva (final)
  7. Karen Deed / Nicole Provis (second round)
  8. Michelle Jaggard / Lisa O'Neill (champions)

Draw

Bottom half

External links

Notes and References

  1. Web site: Girls' Doubles Finals 1982-2017. wimbledon.com. Wimbledon Championships. 5 December 2017.