1986 New York Attorney General election explained

Election Name:1986 New York Attorney General Election
Country:New York
Flag Image:Flag of New York (1909–2020).svg
Type:presidential
Ongoing:no
Previous Election:1982 New York Attorney General election
Previous Year:1982
Next Election:1990 New York Attorney General election
Next Year:1990
Election Date:November 4, 1986
Image1:File:Soundview Abrams, Bronx Borough President (NYPL b11524053-1253146) (cropped).tiff
Nominee1:Robert Abrams
Party1:Democratic Party (United States)
Alliance1:Liberal
Popular Vote1:2,548,386
Percentage1:65.13%
Nominee2:Peter T. King
Party2:Republican Party (United States)
Alliance2:ConservativeRight to Life
Popular Vote2:1,344,344
Percentage2:34.36%
Map Size:305px
New York Attorney General
Before Election:Robert Abrams
Before Party:Democratic Party (United States)
After Election:Robert Abrams
After Party:Democratic Party (United States)

The 1986 New York State Attorney General election took place on November 4, 1986, to elect a candidate to the position of Attorney General. Democratic nominee and incumbent Attorney General Robert Abrams defeated Republican nominee Peter T. King, resulting in the re-election of Abrams to the position of Attorney General.

General election

Candidates

Results

A total of 568,888 blank, void, and scattering votes are not counted for in the election box below.