1986 Minnesota Attorney General election explained

Election Name:1986 Minnesota Attorney General election
Country:Minnesota
Type:Presidential
Ongoing:no
Previous Election:1982 Minnesota Attorney General election
Previous Year:1982
Next Election:1990 Minnesota Attorney General election
Next Year:1990
Election Date:4 November 1986
Nominee1:Hubert Humphrey III
Party1:Minnesota Democratic–Farmer–Labor Party
Popular Vote1:985,569
Percentage1:70.33%
Nominee2:Lewis Freeman
Party2:Republican Party (United States)
Popular Vote2:399,483
Percentage2:28.51%
Attorney General
Before Election:Hubert Humphrey III
Before Party:Minnesota Democratic–Farmer–Labor Party
After Election:Hubert Humphrey III
After Party:Minnesota Democratic–Farmer–Labor Party

The 1986 Minnesota Attorney General election was held on 4 November 1986 in order to elect the attorney general of Minnesota. Democratic–Farmer–Labor nominee and incumbent attorney general Hubert Humphrey III defeated Republican nominee Lewis Freeman and Grassroots nominee Derrick P. Grimmer.[1]

General election

On election day, 4 November 1986, Democratic–Farmer–Labor nominee Hubert Humphrey III won re-election by a margin of 586,086 votes against his foremost opponent Republican nominee Lewis Freeman, thereby retaining Democratic–Farmer–Labor Party control over the office of attorney general. Humphrey was sworn in for his second term on 6 January 1987.[2]

Results

Notes and References

  1. Web site: Attorney General, 1986 Election . electionarchives.lib.umn.edu . 9 October 2024.
  2. Web site: MN Attorney General . ourcampaigns.com . 2 April 2004 . 9 October 2024.