1979 Wimbledon Championships – Women's singles explained

Score:6–4, 6–4
Draw:96 (8 / 6)
Seeds:16
Before Name:Wimbledon Championships – Women's singles
After Name:Wimbledon Championships – Women's singles
Type:grand slam

See main article: 1979 Wimbledon Championships.

Defending champion Martina Navratilova defeated Chris Evert-Lloyd in a rematch of the previous year's final, 6–4, 6–4 to win the ladies' singles tennis title at the 1979 Wimbledon Championships.[1] It was her second Wimbledon singles title and second major singles title overall.

Seeds

See also: 1 and 1. Martina Navratilova (champion)

See also: 2 and 8. Chris Evert Lloyd (final)

See also: 3 and 6. Evonne Goolagong Cawley (semifinals)

See also: 4 and 3. Tracy Austin (semifinals)

See also: 5 and 5. Virginia Wade (quarterfinals)

See also: 6 and 2. Dianne Fromholtz (quarterfinals)

See also: 7 and 4. Billie Jean King (quarterfinals)

See also: 8 and 7. Wendy Turnbull (quarterfinals)

See also: 9 and 7. Kerry Reid (fourth round)

See also: 10 and 3. Virginia Ruzici (fourth round)

See also: 11 and 1. Greer Stevens (fourth round)

See also: 12 and 5. Sue Barker (first round)

See also: 13 and 4. Regina Maršíková (third round)

See also: 14 and 6. Kathy Jordan (fourth round)

See also: 15 and 2. Betty Stöve (fourth round)

See also: 16 and 8. Pam Shriver (second round)

Both Evonne Goolagong Cawley and Billie Jean King were given protected seedings above their actual rankings, as they were returning from almost year-long injury absences.

Qualifying

See main article: 1979 Wimbledon Championships – Women's singles qualifying.

Draw

Top half

Section 4

Bottom half

Section 8

See also

External links

Notes and References

  1. Book: Barrett, John. Wimbledon: The Official History. 2014. Vision Sports Publishing. 9-781909-534230. 4th.