1978 FIFA World Cup knockout stage explained

The knockout stage of 1978 FIFA World Cup was a single-elimination tournament involving the four teams that qualified from the second group stage of the tournament. There were two matches: a third place play-off contested by the group runners-up, and the final to decide the champions, contested by the group winners. The knockout stage began with the third place play-off on 24 June and ended with the final on 25 June 1978, both at the Estadio Monumental in Buenos Aires. Argentina won the tournament with a 3–1 victory over the Netherlands.[1]

All times ART

Qualified teams

The top two placed teams from each of the two groups of the second round qualified for the knockout stage.

Third place play-off

As of the 2022 FIFA World Cup, this is the most recent time when the third place match was won by a non-European team.

See also: Brazil–Italy football rivalry.

GK 1 Émerson Leão (c)
DF 13
DF 3 Oscar
DF 4 Amaral
DF 16 Rodrigues Neto
MF 17
MF 5
MF 11 Dirceu
FW 18
FW 19 Jorge Mendonça
FW 20 Roberto Dinamite
Substitutions:
FW 9
FW 10
Manager:
Cláudio Coutinho
width=25!width=25
GK 1 Dino Zoff (c)
DF 6 Aldo Maldera
DF 3 Antonio Cabrini
DF 5
DF 8 Gaetano Scirea
MF 4 Antonello Cuccureddu
MF 13 Patrizio Sala
MF 9
MF 16 Franco Causio
CF 18 Roberto Bettega
CF 21 Paolo Rossi
Substitutions:
MF 17
Manager:
Enzo Bearzot
Assistant referees


Alfonso González Archundia (Mexico)
Károly Palotai (Hungary)

Final

See main article: 1978 FIFA World Cup Final.

External links

Notes and References

  1. Web site: The story of the 1978 World Cup . 18 May 2010. BBC Sport. 30 April 2014.