1973 Federation Cup (tennis) explained

The 1973 Federation Cup was the 11th edition of the most important competition between national teams in women's tennis. 30 nations participated in the tournament, which was held at the Bad Homburg Tennis Club in Bad Homburg, West Germany from 30 April–6 May. Australia defeated South Africa in the final, winning the title without losing a rubber.[1]

Draw

All ties were played at the Bad Homburg Tennis Club in Bad Homburg, West Germany on clay courts.

First round

Japan vs. Ireland

New Zealand vs. Indonesia

United States vs. Italy

Norway vs. South Korea

Spain vs. Canada

South Africa vs. Greece

Switzerland vs. Belgium

Denmark vs. Yugoslavia

Netherlands vs. France

Sweden vs. Argentina

Romania vs. Brazil

Mexico vs. Austria

Second round

Australia vs. Japan

Luxembourg vs. Indonesia

United States vs. South Korea

Spain vs. West Germany

South Africa vs. Belgium

Denmark vs. Netherlands

Sweden vs. Romania

Mexico vs. Great Britain

Quarterfinals

Australia vs. Indonesia

United States vs. West Germany

South Africa vs. Netherlands

Romania vs. Great Britain

Semifinals

Australia vs. West Germany

South Africa vs. Romania

Final

Australia vs. South Africa

Consolation Round

Teams which lost in the first or second round of the main draw went on to play in the Consolation Round.

First round

Belgium vs. New Zealand

South Korea vs. Switzerland

France vs. Denmark

Luxembourg vs. Brazil

Second round

Sweden vs. Canada

Spain vs. Italy

Belgium vs. South Korea

France vs. Brazil

Greece vs. Ireland

Austria vs. Yugoslavia

Argentina vs. Japan

Quarterfinals

Sweden vs. Norway

South Korea vs. Spain

France vs. Ireland

Austria vs. Japan

Semifinals

Sweden vs. South Korea

France vs. Japan

Final

Sweden vs. Japan

Notes and References

  1. News: 1973 Federation Cup. fedcup.com.