1972 Davis Cup Explained

The 1972 Davis Cup was the 61st edition of the Davis Cup, the most important tournament between national teams in men's tennis. 55 teams would enter the competition, 33 in the Europe Zone, 11 in the Americas Zone, and 11 in the Eastern Zone.

From this year's tournament onward, the Challenge Round was abolished, meaning the defending champion would now play in all matches rather than receiving a bye to the final, and the winner of the Inter-Zonal Zone would win the Davis Cup.

The United States defeated Chile in the Americas Inter-Zonal final, Australia defeated India in the Eastern Inter-Zonal final, and Romania and Spain were the winners of the two Europe Zones, defeating the Soviet Union and Czechoslovakia respectively.

In the Inter-Zonal Zone, the United States defeated Spain and Romania defeated Australia in the semifinals. The United States then defeated Romania in the final, giving the United States their fifth straight title. The final was played at the Club Sportiv Progresul in Bucharest, Romania on 13–15 October.[1] [2]

Americas Zone

Americas Inter-Zonal Final

Chile vs. United States

Eastern Zone

Eastern Inter-Zonal Final

India vs. Australia

Europe Zone

Zone A Final

Soviet Union vs. Romania

Zone B Final

Spain vs. Czechoslovakia

Inter-Zonal Zone

Semifinals

Spain vs. United States

Romania vs. Australia

Final

Romania vs. United States

External links

Notes and References

  1. Book: Bud Collins. The Bud Collins History of Tennis. 2010. New Chapter Press. [New York]. 978-0942257700. 495–496, 499. 2nd.
  2. Book: The Encyclopedia of Tennis. 1974. Allen & Unwin. London. 0047960426. Max Robertson. 384.