1968 Wimbledon Championships – Men's doubles explained

Score:3–6, 8–6, 5–7, 14–12, 6–3
Draw:64 (4)
Seeds:8
Type:grand slam

See main article: 1968 Wimbledon Championships. Bob Hewitt and Frew McMillan were the defending champions, but lost in the semifinals to Ken Rosewall and Fred Stolle.

John Newcombe and Tony Roche beat Rosewall and Stolle in the final, 3–6, 8–6, 5–7, 14–12, 6–3 to win the gentlemen's doubles title at the 1968 Wimbledon Championships.[1]

Seeds

See also: 1 and 1. Roy Emerson / Rod Laver (semifinals)

See also: 2 and 4. Ken Rosewall / Fred Stolle (final)

See also: 3 and 3. Andrés Gimeno / Pancho Gonzales (third round)

See also: 4 and 2. John Newcombe / Tony Roche (champions)

See also: 5 and 2. Butch Buchholz / Dennis Ralston (quarterfinals)

See also: 6 and 3. Bob Hewitt / Frew McMillan (semifinals)

See also: 7 and 4. Tom Okker / Marty Riessen (first round)

See also: 8 and 1. Cliff Drysdale / Roger Taylor (quarterfinals)

Draw

Top half

Section 2

Bottom half

Section 4

External links

Notes and References

  1. Book: Barrett, John. Wimbledon: The Official History. 2014. Vision Sports Publishing. 9-781909-534230. 4th.