| Election Name: | 1968 Missouri Attorney General election |
| Country: | Missouri |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1964 Missouri Attorney General election |
| Previous Year: | 1964 |
| Next Election: | 1972 Missouri Attorney General election |
| Next Year: | 1972 |
| Election Date: | 5 November 1968 |
| Image1: | File:JohnDanforth.jpg |
| Nominee1: | John Danforth |
| Party1: | Republican Party (United States) |
| Popular Vote1: | 891,498 |
| Percentage1: | 52.11% |
| Nominee2: | Norman H. Anderson |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 819,365 |
| Percentage2: | 47.89% |
| Attorney General | |
| Before Election: | Norman H. Anderson |
| Before Party: | Democratic Party (United States) |
| After Election: | John Danforth |
| After Party: | Republican Party (United States) |
The 1968 Missouri Attorney General election was held on 5 November 1968 in order to elect the attorney general of Missouri. Republican nominee John Danforth defeated Democratic nominee and incumbent attorney general Norman H. Anderson.[1]
On election day, 5 November 1968, Republican nominee John Danforth won the election by a margin of 72,133 votes against his opponent Democratic nominee Norman H. Anderson, thereby gaining Republican control over the office of attorney general. Danforth was sworn in as the 37th attorney general of Missouri on 13 January 1969.[2]