1966 United States Senate election in Rhode Island explained

Election Name:1966 United States Senate election in Rhode Island
Country:Rhode Island
Type:presidential
Ongoing:no
Previous Election:1960 United States Senate election in Rhode Island
Previous Year:1960
Next Election:1972 United States Senate election in Rhode Island
Next Year:1972
Election Date:November 8, 1966
Image1:File:Sen Claiborne Pell.jpg
Nominee1:Claiborne Pell
Party1:Democratic Party (United States)
Popular Vote1:219,331
Percentage1:67.66%
Nominee2:Ruth M. Briggs
Party2:Republican Party (United States)
Popular Vote2:104,838
Percentage2:32.34%
Map Size:250px
U.S. Senator
Before Election:Claiborne Pell
Before Party:Democratic Party (United States)
After Election:Claiborne Pell
After Party:Democratic Party (United States)

The 1966 United States Senate election in Rhode Island took place on November 8, 1966. Incumbent Democratic U.S. Senator Claiborne Pell successfully sought re-election, defeating Republican Ruth M. Briggs with 67.66% of the vote.

Primary elections

Primary elections were held on September 13, 1966.

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Results

Bibliography

Notes and References

  1. News: . Rhode Island . Des Moines Tribune . Des Moines, Iowa . 14 September 1966 . 3 . 3 July 2021 .