Election Name: | 1966 United States Senate election in Illinois |
Country: | Illinois |
Flag Year: | 1915 |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1960 United States Senate election in Illinois |
Previous Year: | 1960 |
Next Election: | 1972 United States Senate election in Illinois |
Next Year: | 1972 |
Election Date: | November 8, 1966 |
Nominee1: | Charles Percy |
Party1: | Republican Party (United States) |
Popular Vote1: | 2,100,449 |
Percentage1: | 54.95% |
Nominee2: | Paul Douglas |
Party2: | Democratic Party (United States) |
Popular Vote2: | 1,678,147 |
Percentage2: | 43.90% |
Map Size: | 300x300px |
U.S. Senator | |
Before Election: | Paul Douglas |
Before Party: | Democratic Party (United States) |
After Election: | Charles H. Percy |
After Party: | Republican Party (United States) |
Turnout: | 71.56% |
The 1966 United States Senate election in Illinois took place on November 8, 1966.[1] Incumbent Democratic United States Senator Paul Douglas, seeking a fourth term in the United States Senate, faced off against Republican Charles H. Percy, a businessman and the 1964 Republican nominee for Governor of Illinois. A competitive election ensued, featuring campaign appearances by former vice president Richard M. Nixon on behalf of Percy.[2] Ultimately, Percy ended up defeating Senator Douglas by a fairly wide margin, allowing him to win what would be the first of three terms in the Senate.
The primary (held on June 14) and general election coincided with those for House and state elections.[1]
Turnout in the primaries was 27.13%, with 1,509,302 votes cast.[1] [3]
Turnout during the general election was 71.56%, with a total of 3,822,724 votes cast.[1] [3]
Incumbent Paul Douglas was renominated, running unopposed.
Businessman Charles H. Percy won the Republican primary by a large margin.