1964 United States presidential election in the District of Columbia explained

See main article: 1964 United States presidential election.

Election Name:1964 United States presidential election in the District of Columbia
Country:District of Columbia
Flag Year:1960
Type:presidential
Ongoing:no
Previous Election:1960 United States presidential election in the District of Columbia
Previous Year:1960
(primaries)
Next Election:1968 United States presidential election in the District of Columbia
Next Year:1968
Election Date:November 3, 1964
Image1:37 Lyndon Johnson 3x4 (cropped).jpg
Nominee1:Lyndon B. Johnson
Party1:Democratic Party (United States)
Home State1:Texas
Running Mate1:Hubert Humphrey
Electoral Vote1:3
Popular Vote1:169,796
Percentage1:85.50%
Nominee2:Barry Goldwater
Party2:Republican Party (United States)
Home State2:Arizona
Running Mate2:William E. Miller
Electoral Vote2:0
Popular Vote2:28,801
Percentage2:14.50%
President
Before Election:Lyndon B. Johnson
Before Party:Democratic Party (United States)
After Election:Lyndon B. Johnson
After Party:Democratic Party (United States)
Map Size:250px

The 1964 United States presidential election in the District of Columbia took place on November 3, 1964, as part of the 1964 United States presidential election. District of Columbia voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

President Lyndon B. Johnson won Washington, D.C. by an overwhelming margin, receiving over 85% of the vote. This was the first presidential election in which the District of Columbia had the right to vote. The District of Columbia has voted Democratic by overwhelming margins every time since this election.

This was one of only two elections where Washington, D.C. wasn't the largest margin for either candidate along with 1972, this time being second to a 74.28% margin for Goldwater in Mississippi.

See also

Notes and References

  1. Web site: 1964 Presidential Election Results Washington, D.C..