1962 Iowa gubernatorial election explained

Election Name:1962 Iowa gubernatorial election
Country:Iowa
Flag Image:Flag of Iowa (variant).svg
Type:Presidential
Ongoing:no
Previous Election:1960 Iowa gubernatorial election
Previous Year:1960
Next Election:1964 Iowa gubernatorial election
Next Year:1964
Election Date:November 6, 1962
Image1:File:Harold Hughes, US Senator.jpg
Nominee1:Harold Hughes
Party1:Democratic Party (United States)
Popular Vote1:430,899
Percentage1:52.56%
Nominee2:Norman A. Erbe
Party2:Republican Party (United States)
Popular Vote2:388,955
Percentage2:47.44%
Map Size:240px
Governor
Before Election:Norman Erbe
Before Party:Republican Party (United States)
After Election:Harold Hughes
After Party:Democratic Party (United States)

The 1962 Iowa gubernatorial election was held on November 6, 1962. Democratic nominee Harold Hughes defeated incumbent Republican Norman A. Erbe with 52.56% of the vote.

Primary elections

Primary elections were held on June 4, 1962.[1]

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Results

Notes and References

  1. Web site: Summary of Official Canvass of Votes Cast in Iowa Primary Election . . 1962 . March 22, 2020.