1962 Austrian legislative election explained

Country:Austria
Flag Year:state
Type:parliamentary
Previous Election:1959 Austrian legislative election
Previous Year:1959
Next Election:1966 Austrian legislative election
Next Year:1966
Seats For Election:165 seats in the National Council of Austria
Majority Seats:83
Election Date:18 November 1962
Image1:Alfons_Gorbach_1965.jpg
Leader1:Alfons Gorbach
Party1:Austrian People's Party
Last Election1:44.19%, 79 seats
Seats1:81
Seat Change1: 2
Popular Vote1:2,024,501
Percentage1:45.43%
Swing1: 1.24pp
Leader2:Bruno Pittermann
Party2:Social Democratic Party of Austria
Last Election2:44.79%, 78 seats
Seats2:76
Seat Change2: 2
Popular Vote2:1,960,685
Percentage2:44.00%
Swing2: 0.79pp
Image3:3x4.svg
Leader3:Friedrich Peter
Party3:Freedom Party of Austria
Last Election3:7.70%, 8 seats
Seats3:8
Popular Vote3:313,895
Percentage3:7.04%
Swing3: 0.66pp
Chancellor
Before Election:Alfons Gorbach
Before Party:Austrian People's Party
After Election:Alfons Gorbach
After Party:Austrian People's Party

Parliamentary elections were held in Austria on 18 November 1962.[1] The result was a victory for the Austrian People's Party, which won 81 of the 165 seats. Voter turnout was 94%.[2] Although the People's Party had come up only two seats short of an outright majority, Chancellor Alfons Gorbach (who had succeeded Julius Raab a year earlier) retained the grand coalition with the Socialists under Vice-Chancellor Bruno Pittermann.

Notes and References

  1. Book: Dieter Nohlen

    . Elections in Europe: A data handbook . Nohlen . Dieter . Dieter Nohlen . Stöver . Philip . 31 May 2010 . Nomos Verlagsgesellschaft . 196 . 978-3-8329-5609-7.

  2. Nohlen & Stöver, p214