1960 United States Senate election in Oklahoma explained

Election Name:1960 United States Senate election in Oklahoma
Country:Oklahoma
Flag Image:Flag of Oklahoma (1941–1988).svg
Type:presidential
Ongoing:no
Previous Election:1954 United States Senate election in Oklahoma
Previous Year:1954
Next Election:1964 United States Senate special election in Oklahoma
Next Year:1964 (special)
Election Date:November 8, 1960
Nominee1:Robert S. Kerr
Party1:Democratic Party (United States)
Popular Vote1:474,116
Percentage1:54.84%
Nominee2:B. Hayden Crawford
Party2:Republican Party (United States)
Popular Vote2:385,646
Percentage2:44.61%
U.S. Senator
Before Election:Robert S. Kerr
Before Party:Democratic Party (United States)
After Election:Robert S. Kerr
After Party:Democratic Party (United States)

The 1960 United States Senate election in Oklahoma took place on November 8, 1960. Incumbent Democratic Senator Robert S. Kerr ran for re-election to a third term. He won the Democratic primary in a landslide and then faced former U.S. Attorney B. Hayden Crawford, the Republican nominee, in the general election. Even as Vice President Richard Nixon was winning Oklahoma in a landslide over John F. Kennedy, Kerr was able to defeat Crawford by a wide margin, winning his third term. However, Kerr died just shy of two years into his third term, on January 1, 1963. He was replaced by Governor J. Howard Edmondson in the Senate and a special election was held in 1964.

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Results

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Notes and References

  1. News: February 21, 1960. Considers Race For Kerr's Seat. Miami News-Record. Miami, Okla.. 17. June 18, 2021.
  2. News: April 30, 1960. State Filings In Late Rally Friday. Muskogee Times-Democrat. Muskogee, Okla.. 1. June 18, 2021.