1960 Rhode Island gubernatorial election explained

Election Name:1960 Rhode Island gubernatorial election
Country:Rhode Island
Type:Presidential
Ongoing:no
Previous Election:1958 Rhode Island gubernatorial election
Previous Year:1958
Next Election:1962 Rhode Island gubernatorial election
Next Year:1962
Election Date:November 8, 1960
Image1:File:John Notte (1961).png
Nominee1:John A. Notte Jr.
Party1:Democratic Party (United States)
Popular Vote1:227,318
Percentage1:56.64%
Nominee2:Christopher Del Sesto
Party2:Republican Party (United States)
Popular Vote2:174,044
Percentage2:43.36%
Governor
Before Election:Christopher Del Sesto
Before Party:Republican Party (United States)
After Election:John A. Notte Jr.
After Party:Democratic Party (United States)

The 1960 Rhode Island gubernatorial election was held on November 8, 1960. Democratic nominee John A. Notte Jr. defeated incumbent Republican Christopher Del Sesto with 56.64% of the vote.

Primary elections

Primary elections were held on September 28, 1960.[1]

Democratic primary

Candidates

Results

General election

Candidates

Results

Notes and References

  1. Book: Guide to U.S. Elections . 9781483380353 . April 10, 2020. Kalb . Deborah . 24 December 2015 . CQ Press .