1960 Iowa gubernatorial election explained

Election Name:1960 Iowa gubernatorial election
Country:Iowa
Flag Image:Flag of Iowa (variant).svg
Type:Presidential
Ongoing:no
Previous Election:1958 Iowa gubernatorial election
Previous Year:1958
Next Election:1962 Iowa gubernatorial election
Next Year:1962
Election Date:November 8, 1960
Image1:File:Norman A. Erbe (cropped).jpg
Nominee1:Norman Erbe
Party1:Republican Party (United States)
Popular Vote1:645,026
Percentage1:52.14%
Nominee2:Edward McManus
Party2:Democratic Party (United States)
Popular Vote2:592,063
Percentage2:47.86%
Map Size:240px
Governor
Before Election:Herschel Loveless
Before Party:Democratic Party (United States)
After Election:Norman Erbe
After Party:Republican Party (United States)

The 1960 Iowa gubernatorial election was held on November 8, 1960. Republican nominee Norman A. Erbe defeated Democratic nominee Edward Joseph McManus with 52.14% of the vote.

Primary elections

Primary elections were held on June 6, 1960.[1]

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Results

Notes and References

  1. Web site: Summary of Official Canvass of Votes Cast in Iowa Primary Election . . 1960 . March 25, 2020.