1958 Wimbledon Championships – Men's singles explained

Score:3–6, 6–3, 6–4, 13–11
Draw:128 (10)
Seeds:8
Before Name:Wimbledon Championships – Men's singles
After Name:Wimbledon Championships – Men's singles
Type:grand slam

See main article: 1958 Wimbledon Championships.

Ashley Cooper defeated Neale Fraser in the final, 3–6, 6–3, 6–4, 13–11 to win the gentlemen's singles tennis title at the 1958 Wimbledon Championships.[1] Cooper had to play 332 games to win the title, the most of any male champion in the history of the tournament.[2] Lew Hoad was the defending champion, but was ineligible to compete after turning professional.

Seeds

See also: 1 and 8. Ashley Cooper (champion)

See also: 2 and 1. Mal Anderson (quarterfinals)

See also: 3 and 6. Mervyn Rose (semifinals)

See also: 4 and 3. Neale Fraser (final)

See also: 5 and 7. Luis Ayala (third round)

See also: 6 and 2. Kurt Nielsen (semifinals)

See also: 7 and 4. Sven Davidson (quarterfinals)

See also: 8 and 5. Barry MacKay (quarterfinals)

Draw

Top half

Section 4

Bottom half

Section 8

Notes and References

  1. Book: Barrett, John. Wimbledon: The Official History. 2014. Vision Sports Publishing. 9-781909-534230. 4th.
  2. Web site: Paul Newman. From the archive: Ashley Cooper, Wimbledon's original marathon man. www.wimbledon.com. AELTC. 20 September 2016.