1958 Rhode Island gubernatorial election explained

Election Name:1958 Rhode Island gubernatorial election
Country:Rhode Island
Type:Presidential
Ongoing:no
Previous Election:1956 Rhode Island gubernatorial election
Previous Year:1956
Next Election:1960 Rhode Island gubernatorial election
Next Year:1960
Election Date:November 4, 1958
Image1:File:RI Governor Christopher Del Sesto (cropped).jpg
Nominee1:Christopher Del Sesto
Party1:Republican Party (United States)
Popular Vote1:176,505
Percentage1:50.90%
Nominee2:Dennis J. Roberts
Party2:Democratic Party (United States)
Popular Vote2:170,275
Percentage2:49.10%
Governor
Before Election:Dennis J. Roberts
Before Party:Democratic Party (United States)
After Election:Christopher Del Sesto
After Party:Republican Party (United States)

The 1958 Rhode Island gubernatorial election was held on November 4, 1958. Republican nominee Christopher Del Sesto defeated Democratic incumbent Dennis J. Roberts with 50.90% of the vote. To Roberts 49.10%

Primary elections

Primary elections were held on September 17, 1958.[1]

Democratic primary

Candidates

Results

General election

Candidates

Results

Notes and References

  1. Book: Guide to U.S. Elections . 9781483380353 . April 11, 2020. Kalb . Deborah . 24 December 2015 . CQ Press .